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The isomer of dichlorobenzene which has highest boiling point
a) o-dichlorobenzene
b) p-dichlorobenzene
c) m-dichlorobenzene
d) 1,2 dichlorobenzene
Correct answer is 'B'. Can you explain the answer?
Verified Answer
The isomer of dichlorobenzene which has highest boiling pointa)o-dichl...
Due to symmetrical structure of para-dichloro benzene there exist strong intermolecular forces than in meta- isomer of dichloro benzene. It requires high energy for p-dichloro benzene than m- dichloro benzene to break these bonds during dissolution and boiling. Therefore p-dichlorobenzene has higher boiling point and lower solubility than meta dichlorobenzene.
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Most Upvoted Answer
The isomer of dichlorobenzene which has highest boiling pointa)o-dichl...
Dear friend i think ans should be A, i have data with me boiling point of orthodichlorobenzene is 20Celcius higher than the para isomer .. ......and uf you want the reason it's because ortho isomer has more dipole moment corresponding to hogher boiling point...
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The isomer of dichlorobenzene which has highest boiling pointa)o-dichl...
Isomers of Dichlorobenzene

Dichlorobenzene is a compound with two chlorine atoms attached to a benzene ring. There are three isomers of dichlorobenzene based on the position of the chlorine atoms on the benzene ring:

1. Ortho-dichlorobenzene (o-dichlorobenzene)
2. Meta-dichlorobenzene (m-dichlorobenzene)
3. Para-dichlorobenzene (p-dichlorobenzene)

Melting Point

The melting point of a compound is the temperature at which it changes from a solid to a liquid. The melting point of a compound depends on the strength and type of intermolecular forces between its molecules. Generally, compounds with stronger intermolecular forces have higher melting points.

Answer

The correct answer is option B, p-dichlorobenzene, which has the highest melting point among the three isomers. This is because p-dichlorobenzene has a symmetrical structure that allows for strong intermolecular forces, specifically dipole-dipole interactions.

Explanation

The melting points of the isomers of dichlorobenzene are:

1. Ortho-dichlorobenzene (o-dichlorobenzene) - 53.5°C
2. Meta-dichlorobenzene (m-dichlorobenzene) - -3.7°C
3. Para-dichlorobenzene (p-dichlorobenzene) - 52.6°C

As mentioned earlier, p-dichlorobenzene has a symmetrical structure that allows for strong dipole-dipole interactions. This is because the two chlorine atoms are on opposite sides of the benzene ring, which creates a dipole moment that is evenly distributed across the molecule. This results in a more tightly packed crystal lattice and stronger intermolecular forces, which leads to a higher melting point.

On the other hand, o-dichlorobenzene and m-dichlorobenzene are not symmetrical, which results in weaker intermolecular forces and lower melting points. In o-dichlorobenzene, the two chlorine atoms are adjacent to each other, which can result in steric hindrance and less efficient packing of molecules in the crystal lattice. In m-dichlorobenzene, the two chlorine atoms are separated by one carbon atom, which results in a less evenly distributed dipole moment and weaker intermolecular forces.

In conclusion, p-dichlorobenzene has the highest melting point among the isomers of dichlorobenzene due to its symmetrical structure and strong dipole-dipole interactions.
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The isomer of dichlorobenzene which has highest boiling pointa)o-dichlorobenzeneb)p-dichlorobenzenec)m-dichlorobenzened)1,2 dichlorobenzeneCorrect answer is 'B'. Can you explain the answer?
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