p – Dichlorobenzene has than those of o – and m – is...
The p- isomers being more symmetrical fits closely in the crystal lattice and thus has stronger inter-molecular forces of attraction than o- and m- isomers .
As during melting or dissolution , the crystal lattice breaks , therefore a large amount of energy is needed to melt or dissolve the p - isomer than the corresponding o-and m-isomers .
In other words , the melting point to the p- isomers is higher and its solubility lower than the corresponding o- and- m- isomers.
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p – Dichlorobenzene has than those of o – and m – is...
Higher melting point and lower solubility
Explanation:
Dichlorobenzene is a compound with the molecular formula C6H4Cl2. It exists in three isomeric forms: ortho (o), meta (m), and para (p) isomers. Each isomer has different physical and chemical properties due to the different positions of the chlorine atoms on the benzene ring.
Melting point:
The melting point of a compound is determined by the strength of intermolecular forces between its molecules. In the case of dichlorobenzene, the p-isomer has a higher melting point compared to the o- and m-isomers. This is because the p-isomer has a more symmetrical molecular structure, allowing for stronger intermolecular forces such as dipole-dipole interactions and London dispersion forces. These stronger intermolecular forces result in a higher melting point for the p-isomer.
Solubility:
Solubility is determined by the ability of a compound to interact with the solvent molecules. In the case of dichlorobenzene, the o- and m-isomers have higher solubility compared to the p-isomer. This is because the o- and m-isomers have a polarizable electron cloud, which allows them to interact more favorably with polar solvents through dipole-dipole interactions. On the other hand, the p-isomer has a more symmetrical molecular structure, resulting in a less polarizable electron cloud and weaker dipole-dipole interactions. Therefore, the p-isomer has lower solubility in polar solvents.
In summary, dichlorobenzene has a higher melting point for the p-isomer and lower solubility for the p-isomer compared to the o- and m-isomers.
Therefore, the correct answer is option 'C': higher melting point and lower solubility.