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If (1 − p) is a root of quadratic equation x2 + px + (1 − p) = 0 then its roots are
- a)0, -1
- b)-1, 1
- c)0, 1
- d)-1, 2
- e)2, 3
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
If(1 − p) is a root of quadratic equationx2 + px + (1 − p)...
Given that:
x2 + px + (1 - p) = 0
⇒ x1 = 1 - p
Well,
⇒ (1 – p)2 + p(1 – p) + (1 – p) = 0
(1 - p)(1 – p + p + 1) = 0
2(1 – p) = 0
⇒ p = 1
⇒ x2 + x + 0 = 0
x(x + 1) = 0
x = -1, x = 0
x2 + px + (1 - p) = 0
⇒ x1 = 1 - p
Well,
⇒ (1 – p)2 + p(1 – p) + (1 – p) = 0
(1 - p)(1 – p + p + 1) = 0
2(1 – p) = 0
⇒ p = 1
⇒ x2 + x + 0 = 0
x(x + 1) = 0
x = -1, x = 0
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If(1 − p) is a root of quadratic equationx2 + px + (1 − p) = 0 then its roots area)0, -1b)-1, 1c)0, 1d)-1, 2e)2, 3Correct answer is option 'A'. Can you explain this answer?
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