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A simply supported beam of span 5m has an overhang of 1m at one end.The beam carries a UDL of 10KN/m along the entire length.The maximum bending moment at the 5m span is ANS 26.25KN/m?
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A simply supported beam of span 5m has an overhang of 1m at one end.Th...
Problem Statement:
A simply supported beam of span 5m has an overhang of 1m at one end. The beam carries a UDL of 10KN/m along the entire length. Determine the maximum bending moment at the 5m span.
Solution:
To find the maximum bending moment at the 5m span, we need to consider the different segments of the beam and calculate the bending moment for each segment separately. Then, we can determine the maximum value among them.
Segment 1: Overhang
The overhang segment of length 1m carries the UDL of 10KN/m. The maximum bending moment occurs at the fixed support and is given by the formula:
M_max = wL^2/8
where M_max is the maximum bending moment, w is the UDL, and L is the length of the segment.
Substituting the values, we have:
M_max_overhang = (10 * 1^2)/8 = 1.25 KN/m
Segment 2: Main Span
The main span segment of length 5m also carries the UDL of 10KN/m. The maximum bending moment occurs at the mid-span and is given by the formula:
M_max = wL^2/8
Substituting the values, we have:
M_max_main_span = (10 * 5^2)/8 = 31.25 KN/m
Overall Maximum Bending Moment:
To find the overall maximum bending moment, we compare the bending moments calculated for both segments and choose the larger value.
M_max = max(M_max_overhang, M_max_main_span) = max(1.25, 31.25) = 31.25 KN/m
Therefore, the maximum bending moment at the 5m span is 31.25 KN/m.
Conclusion:
In this problem, we analyzed a simply supported beam with an overhang and a UDL. By considering the bending moments for each segment separately, we determined that the maximum bending moment at the 5m span is 31.25 KN/m.
A simply supported beam of span 5m has an overhang of 1m at one end. The beam carries a UDL of 10KN/m along the entire length. Determine the maximum bending moment at the 5m span.
Solution:
To find the maximum bending moment at the 5m span, we need to consider the different segments of the beam and calculate the bending moment for each segment separately. Then, we can determine the maximum value among them.
Segment 1: Overhang
The overhang segment of length 1m carries the UDL of 10KN/m. The maximum bending moment occurs at the fixed support and is given by the formula:
M_max = wL^2/8
where M_max is the maximum bending moment, w is the UDL, and L is the length of the segment.
Substituting the values, we have:
M_max_overhang = (10 * 1^2)/8 = 1.25 KN/m
Segment 2: Main Span
The main span segment of length 5m also carries the UDL of 10KN/m. The maximum bending moment occurs at the mid-span and is given by the formula:
M_max = wL^2/8
Substituting the values, we have:
M_max_main_span = (10 * 5^2)/8 = 31.25 KN/m
Overall Maximum Bending Moment:
To find the overall maximum bending moment, we compare the bending moments calculated for both segments and choose the larger value.
M_max = max(M_max_overhang, M_max_main_span) = max(1.25, 31.25) = 31.25 KN/m
Therefore, the maximum bending moment at the 5m span is 31.25 KN/m.
Conclusion:
In this problem, we analyzed a simply supported beam with an overhang and a UDL. By considering the bending moments for each segment separately, we determined that the maximum bending moment at the 5m span is 31.25 KN/m.
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A simply supported beam of span 5m has an overhang of 1m at one end.The beam carries a UDL of 10KN/m along the entire length.The maximum bending moment at the 5m span is ANS 26.25KN/m??
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A simply supported beam of span 5m has an overhang of 1m at one end.The beam carries a UDL of 10KN/m along the entire length.The maximum bending moment at the 5m span is ANS 26.25KN/m?? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A simply supported beam of span 5m has an overhang of 1m at one end.The beam carries a UDL of 10KN/m along the entire length.The maximum bending moment at the 5m span is ANS 26.25KN/m?? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A simply supported beam of span 5m has an overhang of 1m at one end.The beam carries a UDL of 10KN/m along the entire length.The maximum bending moment at the 5m span is ANS 26.25KN/m??.
A simply supported beam of span 5m has an overhang of 1m at one end.The beam carries a UDL of 10KN/m along the entire length.The maximum bending moment at the 5m span is ANS 26.25KN/m?? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A simply supported beam of span 5m has an overhang of 1m at one end.The beam carries a UDL of 10KN/m along the entire length.The maximum bending moment at the 5m span is ANS 26.25KN/m?? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A simply supported beam of span 5m has an overhang of 1m at one end.The beam carries a UDL of 10KN/m along the entire length.The maximum bending moment at the 5m span is ANS 26.25KN/m??.
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