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If A and B are square matrices of the same order, then(A+B)2 = A2+2AB+B2 implies
  • a)
    AB + BA = O
  • b)
    AB = O
  • c)
    AB = BA
  • d)
    none of these.
Correct answer is 'A'. Can you explain this answer?
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If A and B are square matrices of the same order, then(A+B)2= A2+2AB+B...
If A and B are square matrices of same order , then , product of the matrices is not commutative.Therefore , the given result is true only when AB = BA.
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If A and B are square matrices of the same order, then(A+B)2= A2+2AB+B...
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If A and B are square matrices of the same order, then(A+B)2= A2+2AB+B...
Explanation:

To prove that the correct answer is option (a), we need to show that the given equation (A B)^2 = A^2 + 2AB + B^2 implies AB + BA = O, where O represents the zero matrix.

Expanding the given equation:

(A B)^2 = A^2 + 2AB + B^2

Expanding the left-hand side of the equation:

(A B)^2 = (A B)(A B)

Using the distributive property of matrix multiplication, we can expand this as:

(A B)(A B) = A(A B) + B(A B)

Now, using the associative property of matrix multiplication, we can further expand this as:

A(A B) + B(A B) = A^2 + AB + BA + B^2

Simplifying the equation:

Now, equating the expanded equation with the given equation:

A^2 + AB + BA + B^2 = A^2 + 2AB + B^2

Subtracting A^2 and B^2 from both sides:

AB + BA = AB

Subtracting AB from both sides:

BA = O

Thus, we have proved that AB + BA = O, which is the required result to show that the correct answer is option (a).

Conclusion:

Therefore, the correct answer is option (a): AB + BA = O.
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If A and B are square matrices of the same order, then(A+B)2= A2+2AB+B2 impliesa)AB + BA = Ob)AB = Oc)AB = BAd)none of these.Correct answer is 'A'. Can you explain this answer?
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