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A bus decelerating with 4m/s2 changes its speed from 60 m s-1 to a certain value in 5 s. The final speed is:
- a)40 m/s
- b)25 m/s
- c)60 m/s
- d)30 m/s
Correct answer is 'A'. Can you explain this answer?
Verified Answer
A bus decelerating with 4m/s2changes its speed from 60 m s-1to a certa...
Acceleration = – 4m/s2; Initial speed, u = 60 m s-1
Time taken = 5s
Acceleration = change in velocity per unit time
a=v-u/t
v= u + at
v = 60 – 4 x 5 = 40 m/s
Most Upvoted Answer
A bus decelerating with 4m/s2changes its speed from 60 m s-1to a certa...
Easy..
u=60ms
t=5's
decreasing it's speed in 4ms²
find = after 5's= 4x5=20ms²
=60-20=40ms
u=60ms
t=5's
decreasing it's speed in 4ms²
find = after 5's= 4x5=20ms²
=60-20=40ms
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Community Answer
A bus decelerating with 4m/s2changes its speed from 60 m s-1to a certa...
Given information:
- Initial speed of the bus, u = 60 m/s
- Deceleration of the bus, a = -4 m/s^2 (negative sign indicates deceleration)
- Time taken, t = 5 s
To find:
- Final speed of the bus
Using the equation of motion:
v = u + at
where:
v = final speed of the bus
u = initial speed of the bus
a = acceleration/deceleration of the bus
t = time taken
Substituting the given values:
v = 60 m/s + (-4 m/s^2)(5 s)
v = 60 m/s - 20 m/s
v = 40 m/s
Hence, the final speed of the bus is 40 m/s.
Explanation:
To solve this problem, we use the equation of motion that relates the final speed, initial speed, acceleration/deceleration, and time taken. In this case, the bus is decelerating, so the acceleration is negative.
By substituting the given values into the equation, we can calculate the final speed of the bus. In this case, the initial speed is 60 m/s, the deceleration is -4 m/s^2, and the time taken is 5 seconds.
After substituting the values and performing the calculations, we find that the final speed of the bus is 40 m/s.
This means that the bus slows down from an initial speed of 60 m/s to a final speed of 40 m/s in a time of 5 seconds, with a deceleration of 4 m/s^2.
- Initial speed of the bus, u = 60 m/s
- Deceleration of the bus, a = -4 m/s^2 (negative sign indicates deceleration)
- Time taken, t = 5 s
To find:
- Final speed of the bus
Using the equation of motion:
v = u + at
where:
v = final speed of the bus
u = initial speed of the bus
a = acceleration/deceleration of the bus
t = time taken
Substituting the given values:
v = 60 m/s + (-4 m/s^2)(5 s)
v = 60 m/s - 20 m/s
v = 40 m/s
Hence, the final speed of the bus is 40 m/s.
Explanation:
To solve this problem, we use the equation of motion that relates the final speed, initial speed, acceleration/deceleration, and time taken. In this case, the bus is decelerating, so the acceleration is negative.
By substituting the given values into the equation, we can calculate the final speed of the bus. In this case, the initial speed is 60 m/s, the deceleration is -4 m/s^2, and the time taken is 5 seconds.
After substituting the values and performing the calculations, we find that the final speed of the bus is 40 m/s.
This means that the bus slows down from an initial speed of 60 m/s to a final speed of 40 m/s in a time of 5 seconds, with a deceleration of 4 m/s^2.
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