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If P(n) = 2 + 4 + 6 + ........ + 2n, n ∈ N, then P(k) = k(k + 1) + 2 ⇒ P(k + 1) = (k + 1)(k + 2) + 2 for all k ∈ N. So, we can conclude that P(n) = n(n + 1) + 2 fora)all n ∈ Nb)n > 1c)n > 2d)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer? for DSSSB TGT/PGT/PRT 2025 is part of DSSSB TGT/PGT/PRT preparation. The Question and answers have been prepared according to the DSSSB TGT/PGT/PRT exam syllabus. Information about If P(n) = 2 + 4 + 6 + ........ + 2n, n ∈ N, then P(k) = k(k + 1) + 2 ⇒ P(k + 1) = (k + 1)(k + 2) + 2 for all k ∈ N. So, we can conclude that P(n) = n(n + 1) + 2 fora)all n ∈ Nb)n > 1c)n > 2d)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for DSSSB TGT/PGT/PRT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If P(n) = 2 + 4 + 6 + ........ + 2n, n ∈ N, then P(k) = k(k + 1) + 2 ⇒ P(k + 1) = (k + 1)(k + 2) + 2 for all k ∈ N. So, we can conclude that P(n) = n(n + 1) + 2 fora)all n ∈ Nb)n > 1c)n > 2d)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer?.

Solutions for If P(n) = 2 + 4 + 6 + ........ + 2n, n ∈ N, then P(k) = k(k + 1) + 2 ⇒ P(k + 1) = (k + 1)(k + 2) + 2 for all k ∈ N. So, we can conclude that P(n) = n(n + 1) + 2 fora)all n ∈ Nb)n > 1c)n > 2d)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for DSSSB TGT/PGT/PRT. Download more important topics, notes, lectures and mock test series for DSSSB TGT/PGT/PRT Exam by signing up for free.

Here you can find the meaning of If P(n) = 2 + 4 + 6 + ........ + 2n, n ∈ N, then P(k) = k(k + 1) + 2 ⇒ P(k + 1) = (k + 1)(k + 2) + 2 for all k ∈ N. So, we can conclude that P(n) = n(n + 1) + 2 fora)all n ∈ Nb)n > 1c)n > 2d)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of If P(n) = 2 + 4 + 6 + ........ + 2n, n ∈ N, then P(k) = k(k + 1) + 2 ⇒ P(k + 1) = (k + 1)(k + 2) + 2 for all k ∈ N. So, we can conclude that P(n) = n(n + 1) + 2 fora)all n ∈ Nb)n > 1c)n > 2d)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for If P(n) = 2 + 4 + 6 + ........ + 2n, n ∈ N, then P(k) = k(k + 1) + 2 ⇒ P(k + 1) = (k + 1)(k + 2) + 2 for all k ∈ N. So, we can conclude that P(n) = n(n + 1) + 2 fora)all n ∈ Nb)n > 1c)n > 2d)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of If P(n) = 2 + 4 + 6 + ........ + 2n, n ∈ N, then P(k) = k(k + 1) + 2 ⇒ P(k + 1) = (k + 1)(k + 2) + 2 for all k ∈ N. So, we can conclude that P(n) = n(n + 1) + 2 fora)all n ∈ Nb)n > 1c)n > 2d)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice If P(n) = 2 + 4 + 6 + ........ + 2n, n ∈ N, then P(k) = k(k + 1) + 2 ⇒ P(k + 1) = (k + 1)(k + 2) + 2 for all k ∈ N. So, we can conclude that P(n) = n(n + 1) + 2 fora)all n ∈ Nb)n > 1c)n > 2d)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice DSSSB TGT/PGT/PRT tests.