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Direction: Read the following information and answer the two questions that follow:
If x cos 2 α + y sin 2α = z has “tanA” and “tanB” as its solution then find
tan A + tan B=?
If x cos 2 α + y sin 2α = z has “tanA” and “tanB” as its solution then find
tan A + tan B=?
- a)y/(x+z)
- b)2y/(x+z)
- c)3y/(x+z)
- d)4y/(x/z)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Direction: Read the following information and answer the two questions...
xcos 2α + y sin2α =z
= x(cos2α -sim2α)+ y(2sin α cosα) = z
Divide both side by cos2α
x(1-tan2α)+ y(2 tanα) = z sec2α = z(1+ tan2α)
= x -x tan2α +2y tanα = z + z tan2α
= tan2α(x + Z)-2ytan α + (z -x) = 0
Clearly we can see that this is a quadratic equation with tanaa as a variable.
This has tanA and tan B as its roots
So sum of roots = tanA + tanB = 2y/(x+z)
= x(cos2α -sim2α)+ y(2sin α cosα) = z
Divide both side by cos2α
x(1-tan2α)+ y(2 tanα) = z sec2α = z(1+ tan2α)
= x -x tan2α +2y tanα = z + z tan2α
= tan2α(x + Z)-2ytan α + (z -x) = 0
Clearly we can see that this is a quadratic equation with tanaa as a variable.
This has tanA and tan B as its roots
So sum of roots = tanA + tanB = 2y/(x+z)
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Direction: Read the following information and answer the two questions that follow:Ifxcos2α+ ysin2α=zhas “tanA” and “tanB” as its solution then findtan A + tan B=?a)y/(x+z)b)2y/(x+z)c)3y/(x+z)d)4y/(x/z)Correct answer is option 'B'. Can you explain this answer?
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Direction: Read the following information and answer the two questions that follow:Ifxcos2α+ ysin2α=zhas “tanA” and “tanB” as its solution then findtan A + tan B=?a)y/(x+z)b)2y/(x+z)c)3y/(x+z)d)4y/(x/z)Correct answer is option 'B'. Can you explain this answer? for DSSSB TGT/PGT/PRT 2025 is part of DSSSB TGT/PGT/PRT preparation. The Question and answers have been prepared according to the DSSSB TGT/PGT/PRT exam syllabus. Information about Direction: Read the following information and answer the two questions that follow:Ifxcos2α+ ysin2α=zhas “tanA” and “tanB” as its solution then findtan A + tan B=?a)y/(x+z)b)2y/(x+z)c)3y/(x+z)d)4y/(x/z)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for DSSSB TGT/PGT/PRT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction: Read the following information and answer the two questions that follow:Ifxcos2α+ ysin2α=zhas “tanA” and “tanB” as its solution then findtan A + tan B=?a)y/(x+z)b)2y/(x+z)c)3y/(x+z)d)4y/(x/z)Correct answer is option 'B'. Can you explain this answer?.
Direction: Read the following information and answer the two questions that follow:Ifxcos2α+ ysin2α=zhas “tanA” and “tanB” as its solution then findtan A + tan B=?a)y/(x+z)b)2y/(x+z)c)3y/(x+z)d)4y/(x/z)Correct answer is option 'B'. Can you explain this answer? for DSSSB TGT/PGT/PRT 2025 is part of DSSSB TGT/PGT/PRT preparation. The Question and answers have been prepared according to the DSSSB TGT/PGT/PRT exam syllabus. Information about Direction: Read the following information and answer the two questions that follow:Ifxcos2α+ ysin2α=zhas “tanA” and “tanB” as its solution then findtan A + tan B=?a)y/(x+z)b)2y/(x+z)c)3y/(x+z)d)4y/(x/z)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for DSSSB TGT/PGT/PRT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction: Read the following information and answer the two questions that follow:Ifxcos2α+ ysin2α=zhas “tanA” and “tanB” as its solution then findtan A + tan B=?a)y/(x+z)b)2y/(x+z)c)3y/(x+z)d)4y/(x/z)Correct answer is option 'B'. Can you explain this answer?.
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