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The first three terms of sequence when nth term tn is n2 – 2n are
- a)–1, 0, 3
- b)1, 0, 2
- c)–1, 0, –3
- d)none of these
Correct answer is 'A'. Can you explain this answer?
Verified Answer
The first three terms of sequence when nth term tn is n2 – 2n ar...
-1,0,3
Step-by-step explanation:
an=n^2-2n=n(n-2)
a1=1(-1)=-1
a2=2(2-2)=0
a3=3(3-2)=3
This question is part of UPSC exam. View all CA Foundation courses
Most Upvoted Answer
The first three terms of sequence when nth term tn is n2 – 2n ar...
Given sequence: tn = n^2 + 2n
We need to find the first three terms of the sequence.
To find the terms, we need to substitute the values of n = 1, 2, and 3 in the given sequence.
a) When n = 1
t1 = 1^2 + 2(1) = 3
b) When n = 2
t2 = 2^2 + 2(2) = 8
c) When n = 3
t3 = 3^2 + 2(3) = 15
Therefore, the first three terms of the sequence are 3, 8, and 15.
Hence, option A is the correct answer.
We need to find the first three terms of the sequence.
To find the terms, we need to substitute the values of n = 1, 2, and 3 in the given sequence.
a) When n = 1
t1 = 1^2 + 2(1) = 3
b) When n = 2
t2 = 2^2 + 2(2) = 8
c) When n = 3
t3 = 3^2 + 2(3) = 15
Therefore, the first three terms of the sequence are 3, 8, and 15.
Hence, option A is the correct answer.
Community Answer
The first three terms of sequence when nth term tn is n2 – 2n ar...
Taking n=1 then 1^2-2^1 = 1-2 =-1
taking n=2 then 2^2- 2^2 =4-4 = 0
taking n=3then 3^2 -2^3 = 9-8= 1
so the answer will be (d) option
taking n=2 then 2^2- 2^2 =4-4 = 0
taking n=3then 3^2 -2^3 = 9-8= 1
so the answer will be (d) option
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