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Find the perimeter of a rhombus, the lengths of whose diagonals are 16cm and 30 cm. The diagonals bisect each other at right angles?
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Find the perimeter of a rhombus, the lengths of whose diagonals are 16...


Perimeter of a Rhombus with Given Diagonals

The perimeter of a rhombus can be calculated by adding the lengths of all four sides. In order to find the perimeter of a rhombus when the lengths of its diagonals are given, we can use the formula:

\[
\text{Perimeter} = 4 \times \text{side length}
\]

where the side length can be calculated using the formula:

\[
\text{Side length} = \sqrt{\left(\frac{\text{Diagonal 1}}{2}\right)^2 + \left(\frac{\text{Diagonal 2}}{2}\right)^2}
\]

Given Diagonals

- Diagonal 1: 16 cm
- Diagonal 2: 30 cm

Calculating Side Length

Using the given diagonals, we can calculate the side length of the rhombus:

\[
\text{Side length} = \sqrt{\left(\frac{16}{2}\right)^2 + \left(\frac{30}{2}\right)^2} = \sqrt{64 + 225} = \sqrt{289} = 17 \text{ cm}
\]

Calculating Perimeter

Now that we have the side length, we can find the perimeter of the rhombus:

\[
\text{Perimeter} = 4 \times \text{side length} = 4 \times 17 = 68 \text{ cm}
\]

Therefore, the perimeter of the rhombus with diagonals of 16 cm and 30 cm is 68 cm.
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Find the perimeter of a rhombus, the lengths of whose diagonals are 16cm and 30 cm. The diagonals bisect each other at right angles?
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