Perimeter of Rhombus with Given Diagonals
The perimeter of a rhombus can be calculated by using the formula:
\[ \text{Perimeter} = 4 \times \text{Side length} \]

Given Information:
- Length of the first diagonal = 16 cm
- Length of the second diagonal = 30 cm

Finding Side Length of the Rhombus:
- The diagonals of a rhombus bisect each other at right angles.
- Using the given diagonals, we can form a right-angled triangle with the side length of the rhombus as one of the legs.
- Applying the Pythagorean theorem, we can find the side length of the rhombus.

Calculations:
\[ \text{Side length} = \sqrt{\left( \frac{16}{2} \right)^2 + \left( \frac{30}{2} \right)^2} \]
\[ \text{Side length} = \sqrt{64 + 225} \]
\[ \text{Side length} = \sqrt{289} \]
\[ \text{Side length} = 17 \text{ cm} \]

Calculating Perimeter:
\[ \text{Perimeter} = 4 \times 17 \]
\[ \text{Perimeter} = 68 \text{ cm} \]
Therefore, the perimeter of the rhombus with diagonals measuring 16 cm and 30 cm is 68 cm.