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Arithmetic mean of three numbers which are in G.P. is 14/3. By adding 1 to the first and second number, and subtracting 1 from the third number, resulting numbers are in A.P. Then sum of squares of original three numbers is
  • a)
    91
  • b)
    364
  • c)
    84
  • d)
    273
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Arithmetic mean of three numbers which are in G.P. is 14/3. By adding ...
Let the three numbers be a, ar, ar2

Also, a + 1, ar+ 1, ar2 - 1 are in A.P.

⇒ a = 2 or a = 8
Hence required numbers are 2,4,8 or 8,4,2
Sum of squares = 4 + 16 ÷ 64 = 84.
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Arithmetic mean of three numbers which are in G.P. is 14/3. By adding 1 to the first and second number, and subtracting 1 from the third number, resulting numbers are in A.P. Then sum of squares of original three numbers isa)91b)364c)84d)273Correct answer is option 'C'. Can you explain this answer?
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