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In the binary equation  ( 1p101)2 + (10q1)2 = (100r100)2
Where p, q and r are binary digits, what are the possible value of p, q and r respectively ? 
  • a)
    0, 1, 0
  • b)
    1, 1, 0
  • c)
    0, 0, 1
  • d)
    1, 0, 1
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In the binary equation ( 1p101)2+ (10q1)2= (100r100)2Where p, q and r ...

according to binary addition rule
(i) 0 +0 = 0
(ii) 0+1 =1
(iii) 1+0 =1
(iv) 1+1 = 0 with a carry of 1
⇒ p,q,r = 0,1,0
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Most Upvoted Answer
In the binary equation ( 1p101)2+ (10q1)2= (100r100)2Where p, q and r ...
Explanation:

Given Binary Equation:
(1p101)2 + (10q1)2 = (100r100)2

Breaking Down the Equation:
- The equation can be expanded and solved by considering the binary addition rules.
- Start by adding the least significant bits first, then move to the left.
- For the given equation, we have:
- 1 + 1 = 0 with a carry of 1
- p + 0 + 1 = 1 (since 1 + 0 + 1 = 10 in binary)
- 0 + q + 1 = 1 (since 0 + 1 + 1 = 10 in binary)
- 1 + 0 = 1
- 1 + 0 = 1
- 0 + 0 = 0

Finding the Values of p, q, and r:
- From the above calculations, we find:
- p = 0
- q = 1
- r = 0

Conclusion:
- Therefore, the possible values of p, q, and r in the binary equation are:
- p = 0
- q = 1
- r = 0
Thus, the correct answer is option 'A' (0, 1, 0).
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In the binary equation ( 1p101)2+ (10q1)2= (100r100)2Where p, q and r are binary digits, what are the possible value of p, q and r respectively ?a)0, 1, 0b)1, 1, 0c)0, 0, 1d)1, 0, 1Correct answer is option 'A'. Can you explain this answer?
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