If the sum of the roots of the quadratic equations mx2 + (2m - 1)x + 4 and (3m + 1)x2 - 6x + (2m - 3) are equal, then find the sum of values of m. 

  • a)
    5/6

  • b)
    1/6

  • c)
    -5/6

  • d)
    Cannot be determined

Correct answer is option 'C'. Can you explain this answer?

CAT Question

Ranveer Singh
Feb 16, 2020
The sum of the roots of a quadratic equation ax2 + bx + c is -b / a
-(2m - 1) / m = 6 / (3m + 1) - 6m2 + m + 1 = 6m - 6m2 - 5m + 1 = 0 m = -1 or 1/6 Thus, the sum of the values of m = -(5/6) Hence, option 3.

Manohar Guri
Jul 06, 2018
Sum of roots for equation a(x*x)+bx+c=0 will be -b/a. so, now we get those two equation sum of roots as (1-2m)/m and 6/(3m+1) now equating them we get an equation as 6(m*m)+5m-1=0 on solving we get m values as -1 and 1/6 upon so adding them up we will get -5/6.

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