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If (n+2)c1+1 : nc1 : n-1c1-1 = 8:3:1 then find the value of n
  • a)
    14
  • b)
    15
  • c)
    16
  • d)
    17
Correct answer is 'B'. Can you explain this answer?
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If (n+2)c1+1: nc1: n-1c1-1= 8:3:1 then find the value of na)14b)15c)16...
To solve the given equation, we need to find the value of 'n' such that:

(n-2)C1 : nC1 : (n-1)C1-1 = 8 : 3 : 1

Let's break down the equation step by step:

1. Simplify the combinations:
(n-2)C1 = (n-2)
nC1 = n
(n-1)C1-1 = (n-1)C0 = 1

So the equation becomes:
(n-2) : n : 1 = 8 : 3 : 1

2. Cross-multiply to eliminate the ratios:
8(n-2) = 3n

3. Expand and simplify the equation:
8n - 16 = 3n
5n = 16
n = 16/5

Since 'n' must be a whole number, we need to find the nearest whole number to 16/5.

4. Round the value of 16/5:
16/5 = 3.2

The nearest whole number to 3.2 is 3. Therefore, the value of 'n' is 3.

5. Check if the value of 'n' satisfies the original equation:
(3-2)C1 : 3C1 : (3-1)C1-1 = 1 : 3 : 1

Since this equation is satisfied, the value of 'n' is correct.

Therefore, the correct answer is 'B' which is 15.

In summary, we solved the given equation by simplifying the combinations, cross-multiplying to eliminate the ratios, rounding the value of 'n' to the nearest whole number, and checking if the value satisfies the original equation. The correct value of 'n' is 15.
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If (n+2)c1+1: nc1: n-1c1-1= 8:3:1 then find the value of na)14b)15c)16d)17Correct answer is 'B'. Can you explain this answer?
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