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Which is the correct order of increasing wave number of the stretching vibrations of (1) C-H (alkane), (2) O-H (alcohol), (3) C=O (ketone), and (4) C≡C (alkyne)?
- a)(4) < (3) < (2) < (1)
- b)(3) < (4) < (2) < (1)
- c)(3) < (4) < (1) < (2)
- d)(4) < (3) < (1) < (2)
Correct answer is option 'C'. Can you explain this answer?
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Which is the correct order of increasing wave number of the stretching...
The stretching vibrations for C-H and O-H bonds are in the ranges 2850-2960 cm-1 and 3200-3600 cm-1, respectively, while those for C=O and C≡C are about 1700 and 2200 cm-1, as summarized.
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Which is the correct order of increasing wave number of the stretching...
Explanation:
Increasing wave number of stretching vibrations is directly related to the strength of the bond. The stronger the bond, the higher the wave number. Let's analyze the given functional groups in order of increasing wave number:
Alkane C-H (1):
- Alkanes have single C-H bonds which are relatively weak.
- The stretching vibration of C-H bond in alkanes has the lowest wave number among the given functional groups.
Alcohol O-H (2):
- Alcohols have O-H bonds which are stronger than C-H bonds due to the higher electronegativity of oxygen.
- The stretching vibration of O-H bond in alcohols has a higher wave number compared to C-H bonds.
Ketone C=O (3):
- Ketones contain a C=O double bond which is stronger than both C-H and O-H bonds.
- The stretching vibration of C=O bond in ketones has a higher wave number than both C-H and O-H bonds.
Alkyne C≡C (4):
- Alkynes contain a triple bond (C≡C) which is the strongest bond among the given functional groups.
- The stretching vibration of C≡C bond in alkynes has the highest wave number compared to all other bonds.
Therefore, the correct order of increasing wave number of the stretching vibrations is:
(3) < (4)="" />< (1)="" />< />
Increasing wave number of stretching vibrations is directly related to the strength of the bond. The stronger the bond, the higher the wave number. Let's analyze the given functional groups in order of increasing wave number:
Alkane C-H (1):
- Alkanes have single C-H bonds which are relatively weak.
- The stretching vibration of C-H bond in alkanes has the lowest wave number among the given functional groups.
Alcohol O-H (2):
- Alcohols have O-H bonds which are stronger than C-H bonds due to the higher electronegativity of oxygen.
- The stretching vibration of O-H bond in alcohols has a higher wave number compared to C-H bonds.
Ketone C=O (3):
- Ketones contain a C=O double bond which is stronger than both C-H and O-H bonds.
- The stretching vibration of C=O bond in ketones has a higher wave number than both C-H and O-H bonds.
Alkyne C≡C (4):
- Alkynes contain a triple bond (C≡C) which is the strongest bond among the given functional groups.
- The stretching vibration of C≡C bond in alkynes has the highest wave number compared to all other bonds.
Therefore, the correct order of increasing wave number of the stretching vibrations is:
(3) < (4)="" />< (1)="" />< />
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Which is the correct order of increasing wave number of the stretching vibrations of (1) C-H (alkane), (2) O-H (alcohol), (3) C=O (ketone), and (4) C≡C (alkyne)?a)(4) < (3) < (2) < (1)b)(3) < (4) < (2) < (1)c)(3) < (4) < (1) < (2)d)(4) < (3) < (1) < (2)Correct answer is option 'C'. Can you explain this answer?
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