In the figure shown above, point E is the intersection point of the di...
Steps 1 & 2: Understand Question and Draw Inferences
In the given rectangle ABCD, we need to find if AB > BC, i.e., if the length is greater than the breadth.
Note that AC and BD are the diagonals of the rectangle and E is their point of intersection.
In right triangle ADC, by Pythagoras Theorem,
AD2 + DC2 = AC2 . . . (1)
Similarly, in right triangle DCB,
DC2 + BC2 = DB2 . . . (2)
Equation (1) – Equation (2):
AD2 – BC2 = AC2 – DB2
Being opposite sides of a rectangle, AD = BC
Therefore, the above equation becomes:
0 = AC2 – DB2Therefore, AC = DB.
Thus, we observe that the two diagonals of the rectangle are equal.
As we know that diagonals of a rectangle bisect each other, we can write
AE = BE = CE = DE = AC/2 = BD/2
(Now, it is also easy to notice that the rectangle is symmetrical about point E.
Therefore, point E will divide each diagonal in half. )
Step 3: Analyze Statement 1
Given AE = 5
Also, given that AB = 7.25
Notice that ABC is a right angled triangle. Applying Pythagoras theorem
AC2 = AB2 + BC2
Therefore, we can calculate the value of BC and so we can arrive at a unique answer on whether AB is greater than BC or not.
Statement 1 is sufficient to arrive at a unique answer.
Step 4: Analyze Statement 2
Perimeter of AEB > Perimeter of BEC
- AE + BE + AB > BE + CE + BC
- AB > BC (Since we already noted that AE = BE = CE = DE)
Statement 2 is sufficient to arrive at a unique answer.
Step 5: Analyze Both Statements Together (if needed)
We arrived at a unique answer in step 3 and step 4 above. Therefore, this step is not needed.
Correct Answer: D