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The speed of overtaking and overtaken vehicles are 90 Kmph and 72 Kmph respectively. Calculate the overtaking sight distance. Assume acceleration of overtaking vehicle as 0.8 m/s2 and traffic stream moves in one way.
  • a)
    230 m
  • b)
    280 m
  • c)
    480 m
  • d)
    530 m
Correct answer is 'B'. Can you explain this answer?
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Calculation for Overtaking Sight Distance

Given data:

Speed of overtaking vehicle (V1) = 90 kmph = 25 m/s

Speed of overtaken vehicle (V2) = 72 kmph = 20 m/s

Acceleration of overtaking vehicle (a) = 0.8 m/s^2

Formula:

Overtaking sight distance (S) = [(V1^2 - V2^2)/(2a)] + (V1* t)

Where t = reaction time of driver = 2 seconds

Calculation:

Substituting the given values in the formula,

S = [(25^2 - 20^2)/(2*0.8)] + (25*2)

S = 280 meters

Therefore, the overtaking sight distance is 280 meters.
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