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When two independent pure lines of pea with white flowers are crossed, the F1 progeny has purple flowers. The F2 progeny obtained from selfing shows both purple and white flower in a ratio of 9
∶ 
7. The following conclusions were made:
P. Two different genes are involved, mutations in which lead to formation of white flowers.
Q. These two genes show independent assortment.
R. This is an example of complementary gene action.
S. This is an example of duplicate genes.
Which of the above conclusions are correct? 
  • a)
    P and R only
  • b)
    P and S only
  • c)
    P, Q and S
  • d)
    P, Q and R
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
When two independent pure lines of pea with white flowers are crossed,...
Concept:
  • Duplicate recessive epistasis occurs when recessive alleles at either of the two loci can hide the expression of dominant alleles at the two loci.
  • This is also known as complementary epistasis.  
  • The principle of Independent Assortment describes how different genes independently separate from one another when reproductive cells develop.
  • Independent assortment of genes and their corresponding traits was first observed by Gregor Mendel in 1865 during his studies of genetics in pea plants.
Explanation:
  • The best example of duplicate recessive epistasis is found for flower color in sweet pea plants.
  • The purple color of the sweet pea flower is controlled by two dominant genes, consider A and B.
  • When these genes are present in separate individuals (AAbb or aaBB) or recessive (aabb), they produce white flowers. 
  • A cross between a purple flower (AABB) and a white flower (aabb) strain produced purple color in the F
    1
     generation.
  • Inter-mating of the F1 plants produced purple and white flower plants in 9 : 7 ratio in the F
    2
     generation. 
     
  • Here, recessive allele a is epistatic to B/b alleles and hides or masks the expression of these alleles. Another recessive allele, b, act as an epistatic allele to A/a alleles and mask their expression. 
  • Hence in F
    2
     generation, plants with A_B_ (9/16) genotypes will have purple flowers, and plants with aaB_ (3/16), A_bb (3/16), and aabb (1/16) genotypes produce white flowers
    .  
  • As a result, only two phenotypic classes, viz., purple and white, are produced, and the normal dihybrid ratio of 9 : 3 : 3 : 1 is changed to 9 : 7 in the F
    2
     generation. 
  • Also independent assortment is phenomenon occuring without which we cannot observe the above ratios.
 
 hence the correct answer is option 
4  SO,  statements 
P, Q and R
 
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Most Upvoted Answer
When two independent pure lines of pea with white flowers are crossed,...
Explanation:

Genetic Cross:
- When two independent pure lines of pea with white flowers are crossed, the F1 progeny has purple flowers.
- The F2 progeny obtained from selfing shows both purple and white flowers in a ratio of 9:7.

Conclusions:

P. Two different genes are involved, mutations in which lead to formation of white flowers:
- This conclusion is correct as the presence of white flowers in the F2 progeny indicates the involvement of two different genes responsible for flower color.

Q. These two genes show independent assortment:
- This conclusion is correct as the genes responsible for flower color are on different chromosomes and therefore show independent assortment during gamete formation.

R. This is an example of complementary gene action:
- This conclusion is incorrect as complementary gene action occurs when two different genes work together to produce a single phenotype, which is not the case in this scenario.

S. This is an example of duplicate genes:
- This conclusion is incorrect as duplicate genes refer to multiple copies of the same gene, not two different genes responsible for a trait.
Therefore, the correct conclusions are P, Q, and R.
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When two independent pure lines of pea with white flowers are crossed, the F1 progeny has purple flowers. The F2 progeny obtained from selfing shows both purple and white flower in a ratio of 9 ∶7. The following conclusions were made: P. Two different genes are involved, mutations in which lead to formation of white flowers. Q. These two genes show independent assortment. R. This is an example of complementary gene action. S.This is an example of duplicate genes. Which of the above conclusions are correct?a)P and R onlyb)P and S onlyc)P, Q and Sd)P, Q and RCorrect answer is option 'D'. Can you explain this answer?
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When two independent pure lines of pea with white flowers are crossed, the F1 progeny has purple flowers. The F2 progeny obtained from selfing shows both purple and white flower in a ratio of 9 ∶7. The following conclusions were made: P. Two different genes are involved, mutations in which lead to formation of white flowers. Q. These two genes show independent assortment. R. This is an example of complementary gene action. S.This is an example of duplicate genes. Which of the above conclusions are correct?a)P and R onlyb)P and S onlyc)P, Q and Sd)P, Q and RCorrect answer is option 'D'. Can you explain this answer? for Software Development 2025 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about When two independent pure lines of pea with white flowers are crossed, the F1 progeny has purple flowers. The F2 progeny obtained from selfing shows both purple and white flower in a ratio of 9 ∶7. The following conclusions were made: P. Two different genes are involved, mutations in which lead to formation of white flowers. Q. These two genes show independent assortment. R. This is an example of complementary gene action. S.This is an example of duplicate genes. Which of the above conclusions are correct?a)P and R onlyb)P and S onlyc)P, Q and Sd)P, Q and RCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Software Development 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When two independent pure lines of pea with white flowers are crossed, the F1 progeny has purple flowers. The F2 progeny obtained from selfing shows both purple and white flower in a ratio of 9 ∶7. The following conclusions were made: P. Two different genes are involved, mutations in which lead to formation of white flowers. Q. These two genes show independent assortment. R. This is an example of complementary gene action. S.This is an example of duplicate genes. Which of the above conclusions are correct?a)P and R onlyb)P and S onlyc)P, Q and Sd)P, Q and RCorrect answer is option 'D'. Can you explain this answer?.
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