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One red flag, three white flags and two blue flags are arranged in a line such that,
A. no two adjacent flags are of the same colour
B. the flags at the two ends of the line are of different colours.
In how many different ways can the flags be arranged?
  • a)
    6
  • b)
    4
  • c)
    10
  • d)
    2
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
One red flag, three white flags and two blue flags are arranged in a l...
The three white flags can be arranged in the following two ways:
__ W __ W __ W or W __ W __ W __
In the blanks, the 2 blue and one red flag can be arranged in 3 ways.
So, the total number of arrangements is 2*3 = 6
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Most Upvoted Answer
One red flag, three white flags and two blue flags are arranged in a l...
Approach:
To solve this problem, we need to consider the restrictions given in the question and count the possible arrangements accordingly.

Restrictions:
- No two adjacent flags can be of the same color.
- The flags at the two ends of the line must be of different colors.

Solution:
- We have 3 different colors of flags: red, white, and blue.
- Let's consider the possible arrangements for the first two flags at the ends:
- If the first flag is red, the last flag can be either white or blue.
- If the first flag is white, the last flag can be either red or blue.
- If the first flag is blue, the last flag can be either red or white.
- For each case of the first two flags at the ends, we have 2 possibilities for the middle flag.
- Therefore, the total number of possible arrangements is 3 * 2 = 6.

Conclusion:
Therefore, there are 6 different ways in which the flags can be arranged satisfying the given conditions. Hence, the correct answer is option 'a) 6'.
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