If 2s : 3t is the duplicate ratio of 2s – p : 3t – p thena...
If given ratio x : y then it's duplicate
ratio = x^2 : y^2
According to the problem given,
2s / 3t = ( 2s -p)^2 / (3t -p)^2
2s( 3t -p )^2 = 3t( 2s - p )^2
2s( 9t^2 - 6tp + p^2 ) = 3t(4s^2 -4sp+ p^2)
18st^2-12spt+2p^2s= 12s^2t-12spt+3p^2t
18st^2-12s^2t= 3p^2t - 2p^2s
6st(3t -2s) = p^2(3t - 2s)
6st = p^2
Therefore ,
p^2 = 6st
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If 2s : 3t is the duplicate ratio of 2s – p : 3t – p thena...
Given: 2s : 3t is the duplicate ratio of 2s p : 3t p
To find: The value of p
Solution:
Duplicate ratio means the ratio of the squares of the terms of the original ratio.
The original ratio is 2s : 3t, so its square is (2s)^2 : (3t)^2 = 4s^2 : 9t^2
The duplicate ratio is 2s p : 3t p, so its square is (2s p)^2 : (3t p)^2 = 4s^2 p^2 : 9t^2 p^2
We know that the duplicate ratio is equal to the ratio of the squares of the terms of the original ratio, so:
4s^2 p^2 : 9t^2 p^2 = 4s^2 : 9t^2
Divide both sides by p^2:
4s^2 : 9t^2 = 4s^2 : 9t^2
This equation is true for all values of s and t, so we cannot solve for p.
However, we can check which option is true by substituting some values of s, t, and p.
Let's assume s = 1, t = 2, and p = 3:
Original ratio: 2s : 3t = 2(1) : 3(2) = 2 : 6 = 1 : 3
Square of original ratio: 1^2 : 3^2 = 1 : 9
Duplicate ratio: 2s p : 3t p = 2(1)(3) : 3(2)(3) = 6 : 18 = 1 : 3
Square of duplicate ratio: 1^2 : 3^2 = 1 : 9
So, the given condition is satisfied for these values of s, t, and p.
Now, let's check which option is true:
a) p^2 = 6st
Substitute s = 1, t = 2, and p = 3:
p^2 = 6(1)(2) = 12, which is not true.
b) p = 6st
Substitute s = 1, t = 2, and p = 3:
p = 6(1)(2) = 12, which is not true.
c) 2p = 3t
Substitute s = 1, t = 2, and p = 3:
2p = 3(2), which is not true.
d) None of these
This option seems to be true, as options a, b, and c are not true for the given values of s, t, and p.
Therefore, the correct answer is option d) none of these.
If 2s : 3t is the duplicate ratio of 2s – p : 3t – p thena...
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