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Two identical capacitors are joined in parallel, charged to a potential V, separated and then, connected in series, i.e., the positive plate of one is connected to the negative plate of the other. Then:
  • a)
    the charges on the free plates connected togetherare destroyed
  • b)
    charges on the free plates are destroyed
  • c)
    the energy stored in the system increases
  • d)
    the potential difference between the free plates is 2V
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Two identical capacitors are joined in parallel, charged to a potentia...
Explanation:

When two identical capacitors are joined in parallel, the potential difference across each capacitor is the same, and the charge on each plate is given by Q = CV, where C is the capacitance of each capacitor.

When the capacitors are separated and connected in series, the potential difference across the combination is 2V (the sum of the potential differences across each capacitor), and the charge on each plate is still Q = CV.

Now, when the free plates (i.e., the plates not connected to the circuit) are connected together, the charges on those plates are destroyed. This is because the charges will flow through the circuit until the potential difference across each capacitor is equal to V, which means that the charge on each plate will be reduced to half of its original value.

Therefore, option 'A' is the correct answer.

Summary:

- When two identical capacitors are joined in parallel, the potential difference across each capacitor is the same, and the charge on each plate is given by Q = CV.
- When the capacitors are separated and connected in series, the potential difference across the combination is 2V, and the charge on each plate is still Q = CV.
- When the free plates are connected together, the charges on those plates are destroyed because they will flow through the circuit until the potential difference across each capacitor is equal to V.
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Two identical capacitors are joined in parallel, charged to a potentia...
yaaa... it is corrct As two capacitor are charged to same potential so they have same charge. therefore when they are connected in series the -ve and +ve plate have same charge hence neutralise
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Two identical capacitors are joined in parallel, charged to a potential V, separated and then, connected in series, i.e., the positive plate of one is connected to the negative plate of the other. Then:a)the charges on the free plates connected togetherare destroyedb)charges on the free plates are destroyedc)the energy stored in the system increasesd)the potential difference between the free plates is 2VCorrect answer is option 'A'. Can you explain this answer?
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