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The rate of diffusion of methane at a given temperature is twice that of a gas X. The molecular weight of X is:
  • a)
    64.0
  • b)
    32.0
  • c)
    4.0
  • d)
    8.0
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The rate of diffusion of methane at a given temperature is twice that ...
rate is proportional to inverse of sqrt of mass of gas. r1/r2 = sqrt (Mx/Mmethane) 4 = Mx/Mmethane =>Mx = 4*16 = 64 (mass of methane=16) 
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The rate of diffusion of methane at a given temperature is twice that ...
Because of rate is inversly proportional to square root of molecular waightGiven. R1=2 R2. And M1=16 then 2 R2/R2= sq.root of M2/M1,,,put velue ans 64
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The rate of diffusion of methane at a given temperature is twice that of a gas X. The molecular weight of X is:a)64.0b)32.0c)4.0d)8.0Correct answer is option 'A'. Can you explain this answer?
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