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X was issued 100 shares of Rs. 10 each at a premium of Re.1, he paid application money and allotment money which in total amounted to Rs. 5 (excluding premium) and failed to pay the balance call money of Rs. 5. Find the maximum discount that can be given at the time reissue of shares: 
  • a)
    Rs. 4 per shares 
  • b)
    Rs. 5 per share
  • c)
    Rs. 2 per share 
  • d)
    Rs. 6 per share 
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
X was issued 100 shares of Rs. 10 each at a premium of Re.1, he paid a...
Total price of per share= 5+1(as security premium)+5(as call money) = 11
Paid by X is 5+1(as security premium)= 6
Maximum discount can be givem = 11- 6= 5
Correct option is 'B'
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X was issued 100 shares of Rs. 10 each at a premium of Re.1, he paid a...
Given:
X was issued 100 shares of Rs. 10 each at a premium of Re.1.
He paid application money and allotment money which in total amounted to Rs. 5 (excluding premium).
He failed to pay the balance call money of Rs. 5.

To Find:
The maximum discount that can be given at the time of reissue of shares.

Solution:
To find the maximum discount that can be given at the time of reissue of shares, we need to calculate the total amount paid by X for the shares and subtract it from the total face value of the shares.

Calculation:
1. Face value of 100 shares = Rs. 10 each
Total face value = 100 x 10 = Rs. 1000

2. Premium on 100 shares = Re. 1 each
Total premium = 100 x 1 = Rs. 100

3. Application money + Allotment money = Rs. 5 (excluding premium)
Let the application money be x and the allotment money be y.
So, x + y = 5

4. The balance call money not paid = Rs. 5

5. Total amount paid by X for the shares = Application money + Allotment money + Premium
Total amount paid = x + y + 100 = x + y + 100

6. The maximum discount that can be given at the time of reissue of shares = Total face value - Total amount paid
Maximum discount = (1000 + 100) - (x + y + 100)
Maximum discount = 1100 - (x + y + 100)
Maximum discount = 1000 - (x + y)

7. We need to find the maximum discount, so we need to minimize the value of (x + y).

8. Given that x + y = 5, we need to find the minimum value of (x + y) such that it is less than or equal to 5.

9. The minimum value of (x + y) is 5 when x = 0 and y = 5.

10. Substituting the values of x = 0 and y = 5 in the equation for maximum discount:
Maximum discount = 1000 - (0 + 5)
Maximum discount = 1000 - 5
Maximum discount = 995

Therefore, the maximum discount that can be given at the time of reissue of shares is Rs. 995.

Conclusion:
The maximum discount that can be given at the time of reissue of shares is Rs. 995.
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X was issued 100 shares of Rs. 10 each at a premium of Re.1, he paid application money and allotment money which in total amounted to Rs. 5 (excluding premium) and failed to pay the balance call money of Rs. 5. Find the maximum discount that can be given at the time reissue of shares:a)Rs. 4 per sharesb)Rs. 5 per sharec)Rs. 2 per shared)Rs. 6 per shareCorrect answer is option 'B'. Can you explain this answer?
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