RRB NTPC/ASM/CA/TA Exam > RRB NTPC/ASM/CA/TA Questions > a)0.668b)2.99c)0.167d)7e)none of theseCorrect...
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- a)0.668
- b)2.99
- c)0.167
- d)7
- e)none of these
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
a)0.668b)2.99c)0.167d)7e)none of theseCorrect answer is option 'B'. Ca...
Let 4.669 be a and 2.331 be B
then the whole term becomes like
a²-b²/a²+b²-2ab
= (a-b)(a+b) / (a-b)²
= (a+b) / (a-b)
= 4.669 + 2.331 / 4.669 - 2.331
= 7/2.338 = 2.99
then the whole term becomes like
a²-b²/a²+b²-2ab
= (a-b)(a+b) / (a-b)²
= (a+b) / (a-b)
= 4.669 + 2.331 / 4.669 - 2.331
= 7/2.338 = 2.99
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a)0.668b)2.99c)0.167d)7e)none of theseCorrect answer is option 'B'. Ca...
The dinominator is in the form (a-b)^2 = a^2 + b^2 - 2ab
therefore a = 4.669 , b = 2.331
from nuemarator
4.669 × 4.669 = (4.669)^2
2.331 × 2.331 = (2.331)^2
now nuemarator is in the form a^2 - b^2 = (a+b)(a-b)
the question can be rearranged as,
(a+b)(a-b)/(a-b)^2
q (a-b) can be cancelled from nuemarator and dinominator then the question become
(a+b)/(a-b)
subsitutting the values of a and b
4.669 + 2.331/4.669 - 2.331
7/2.338
=. 2.99
hence the solution
therefore a = 4.669 , b = 2.331
from nuemarator
4.669 × 4.669 = (4.669)^2
2.331 × 2.331 = (2.331)^2
now nuemarator is in the form a^2 - b^2 = (a+b)(a-b)
the question can be rearranged as,
(a+b)(a-b)/(a-b)^2
q (a-b) can be cancelled from nuemarator and dinominator then the question become
(a+b)/(a-b)
subsitutting the values of a and b
4.669 + 2.331/4.669 - 2.331
7/2.338
=. 2.99
hence the solution
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a)0.668b)2.99c)0.167d)7e)none of theseCorrect answer is option 'B'. Can you explain this answer?
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