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If we want to insert 8 numbers between the numbers 4 and 31 such that the resulting sequence is an AP.The difference between the consecutive numbers will be
  • a)
    4
  • b)
    3
  • c)
    2
  • d)
    5
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If we want to insert 8 numbers between the numbers 4 and 31 such that ...
a = 4, l = 31, n = 8
(l-a)/(n+1) = (31-4)/(8+1)
= 27/9 
= 3
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Most Upvoted Answer
If we want to insert 8 numbers between the numbers 4 and 31 such that ...
31=4+9d
9d=27
d=27/9
d=3
as we have to take 4 as a first term and 31 as a last term. than total Term equal to 10
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Community Answer
If we want to insert 8 numbers between the numbers 4 and 31 such that ...
Explanation:

Given: We need to insert 8 numbers between 4 and 31 such that the resulting sequence is an AP.

Formula for Arithmetic Progression (AP):
In an AP, the difference between consecutive terms is constant.

Calculation:
1. Given two terms are 4 and 31.
2. We need to insert 8 numbers between them.
3. Total number of terms in the sequence = 2 (given terms) + 8 (numbers to be inserted) = 10.
4. Common difference (d) = (31 - 4) / 9 = 27 / 9 = 3.
Therefore, the difference between consecutive numbers in the resulting sequence will be 3 (option B).
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If we want to insert 8 numbers between the numbers 4 and 31 such that the resulting sequence is an AP.The difference between the consecutive numbers will bea)4b)3c)2d)5Correct answer is option 'B'. Can you explain this answer?
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