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White phosphorus reacts with caustic soda to produce PH₃ and NaH₂PO₄. The reaction is an example for
- a)oxidation
- b)reduction
- c)neutralisation
- d)oxidation-reduction
Correct answer is option 'D'. Can you explain this answer?
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White phosphorus reacts with caustic soda to produce PH and NaHPO. The...
Explanation:
White phosphorus reacts with caustic soda to produce PH and NaHPO. This reaction is an example of an oxidation-reduction reaction. Let's break down the reaction and explain why it is classified as an oxidation-reduction reaction.
- White Phosphorus (P4): White phosphorus is a reducing agent in this reaction. It undergoes oxidation during the reaction by losing electrons.
- Caustic Soda (NaOH): Caustic soda is a strong base that acts as an oxidizing agent in this reaction. It gains electrons during the reaction.
- PH and NaHPO: The products of the reaction, PH and NaHPO, are formed as a result of the transfer of electrons from white phosphorus to caustic soda. This transfer of electrons indicates that oxidation and reduction are taking place simultaneously.
- Oxidation: White phosphorus is oxidized as it loses electrons during the reaction.
- Reduction: Caustic soda is reduced as it gains electrons during the reaction.
Therefore, the reaction between white phosphorus and caustic soda involves the transfer of electrons from one reactant to another, leading to oxidation and reduction processes occurring simultaneously. This is why the reaction is classified as an oxidation-reduction reaction.
White phosphorus reacts with caustic soda to produce PH and NaHPO. This reaction is an example of an oxidation-reduction reaction. Let's break down the reaction and explain why it is classified as an oxidation-reduction reaction.
- White Phosphorus (P4): White phosphorus is a reducing agent in this reaction. It undergoes oxidation during the reaction by losing electrons.
- Caustic Soda (NaOH): Caustic soda is a strong base that acts as an oxidizing agent in this reaction. It gains electrons during the reaction.
- PH and NaHPO: The products of the reaction, PH and NaHPO, are formed as a result of the transfer of electrons from white phosphorus to caustic soda. This transfer of electrons indicates that oxidation and reduction are taking place simultaneously.
- Oxidation: White phosphorus is oxidized as it loses electrons during the reaction.
- Reduction: Caustic soda is reduced as it gains electrons during the reaction.
Therefore, the reaction between white phosphorus and caustic soda involves the transfer of electrons from one reactant to another, leading to oxidation and reduction processes occurring simultaneously. This is why the reaction is classified as an oxidation-reduction reaction.
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White phosphorus reacts with caustic soda to produce PH and NaHPO. The reaction is an example fora)oxidationb)reductionc)neutralisationd)oxidation-reductionCorrect answer is option 'D'. Can you explain this answer?
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