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Joseph Jog from one end A to the other end B of a straight 300m road in 2 min 30 sec and then turns around and jogs 100m back to point C in another 1min . what are Joseph's average speed and velocity in jogging from A to B. and from A to C?
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Joseph Jog from one end A to the other end B of a straight 300m road i...
Speed and Velocity Calculation for Joseph's Jog
Given Data:
- Distance from A to B = 300m
- Time taken to jog from A to B = 2 min 30 sec = 150 sec
- Distance from A to C = 100m
- Time taken to jog from A to C = 1 min = 60 sec
Speed Calculation:
- Speed is calculated as the total distance covered divided by the total time taken.
- For jogging from A to B:
- Speed = Distance / Time = 300m / 150 sec = 2 m/s
- For jogging from A to C:
- Speed = Distance / Time = 100m / 60 sec = 1.67 m/s
Velocity Calculation:
- Velocity is a vector quantity that includes both the speed and direction of an object.
- In this case, the direction is from A to B and from A to C.
- For jogging from A to B:
- Velocity is the displacement (final position - initial position) divided by the total time taken.
- Displacement from A to B = 300m (since it's a straight road)
- Velocity = Displacement / Time = 300m / 150 sec = 2 m/s
- For jogging from A to C:
- Displacement from A to C = 100m
- Velocity = Displacement / Time = 100m / 60 sec = 1.67 m/s
Therefore, Joseph's average speed in jogging from A to B is 2 m/s, and from A to C is 1.67 m/s. His velocity in jogging from A to B is also 2 m/s, and from A to C is 1.67 m/s. Joseph's speed is constant throughout the jog, but his velocity takes into account the direction of his movement.
Given Data:
- Distance from A to B = 300m
- Time taken to jog from A to B = 2 min 30 sec = 150 sec
- Distance from A to C = 100m
- Time taken to jog from A to C = 1 min = 60 sec
Speed Calculation:
- Speed is calculated as the total distance covered divided by the total time taken.
- For jogging from A to B:
- Speed = Distance / Time = 300m / 150 sec = 2 m/s
- For jogging from A to C:
- Speed = Distance / Time = 100m / 60 sec = 1.67 m/s
Velocity Calculation:
- Velocity is a vector quantity that includes both the speed and direction of an object.
- In this case, the direction is from A to B and from A to C.
- For jogging from A to B:
- Velocity is the displacement (final position - initial position) divided by the total time taken.
- Displacement from A to B = 300m (since it's a straight road)
- Velocity = Displacement / Time = 300m / 150 sec = 2 m/s
- For jogging from A to C:
- Displacement from A to C = 100m
- Velocity = Displacement / Time = 100m / 60 sec = 1.67 m/s
Therefore, Joseph's average speed in jogging from A to B is 2 m/s, and from A to C is 1.67 m/s. His velocity in jogging from A to B is also 2 m/s, and from A to C is 1.67 m/s. Joseph's speed is constant throughout the jog, but his velocity takes into account the direction of his movement.
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Joseph Jog from one end A to the other end B of a straight 300m road in 2 min 30 sec and then turns around and jogs 100m back to point C in another 1min . what are Joseph's average speed and velocity in jogging from A to B. and from A to C?
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Joseph Jog from one end A to the other end B of a straight 300m road in 2 min 30 sec and then turns around and jogs 100m back to point C in another 1min . what are Joseph's average speed and velocity in jogging from A to B. and from A to C? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Joseph Jog from one end A to the other end B of a straight 300m road in 2 min 30 sec and then turns around and jogs 100m back to point C in another 1min . what are Joseph's average speed and velocity in jogging from A to B. and from A to C? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Joseph Jog from one end A to the other end B of a straight 300m road in 2 min 30 sec and then turns around and jogs 100m back to point C in another 1min . what are Joseph's average speed and velocity in jogging from A to B. and from A to C?.
Joseph Jog from one end A to the other end B of a straight 300m road in 2 min 30 sec and then turns around and jogs 100m back to point C in another 1min . what are Joseph's average speed and velocity in jogging from A to B. and from A to C? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Joseph Jog from one end A to the other end B of a straight 300m road in 2 min 30 sec and then turns around and jogs 100m back to point C in another 1min . what are Joseph's average speed and velocity in jogging from A to B. and from A to C? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Joseph Jog from one end A to the other end B of a straight 300m road in 2 min 30 sec and then turns around and jogs 100m back to point C in another 1min . what are Joseph's average speed and velocity in jogging from A to B. and from A to C?.
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