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Joseph jogs from one end A to the other end B of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C?
Most Upvoted Answer
Joseph jogs from one end A to the other end B of a straight 300m road ...
Joseph's Average Speed and Velocity Calculation:
From A to B:
- Distance from A to B = 300m
- Time taken = 2 minutes 30 seconds = 150 seconds
- Speed = Distance/Time = 300m/150s = 2 m/s
- Velocity is a vector quantity and is given by displacement/time
- As Joseph jogs in a straight line from A to B, the displacement is also 300m
- Velocity = Displacement/Time = 300m/150s = 2 m/s (in the direction from A to B)
From A to C:
- Distance from A to C = 300m (A to B) + 100m (B to C) = 400m
- Time taken = 2 minutes 30 seconds (A to B) + 1 minute (B to C) = 210 seconds
- Speed = Total Distance/Total Time = 400m/210s ≈ 1.90 m/s
- Velocity is a vector quantity, and for the total journey from A to C, the displacement is 100m (from A to C)
- Velocity = Displacement/Total Time = 100m/210s ≈ 0.476 m/s (in the direction from A to C)
Explanation:
- Joseph's average speed from A to B is 2 m/s, which means he covers 2 meters in one second on average.
- Joseph's average speed from A to C is slightly lower at 1.90 m/s, considering the additional distance covered in the same total time.
- The velocity from A to B and from A to C are the same in magnitude (2 m/s and 1.90 m/s, respectively) as they represent the rate of change of position. However, the direction of the velocity vector differs based on the journey.
From A to B:
- Distance from A to B = 300m
- Time taken = 2 minutes 30 seconds = 150 seconds
- Speed = Distance/Time = 300m/150s = 2 m/s
- Velocity is a vector quantity and is given by displacement/time
- As Joseph jogs in a straight line from A to B, the displacement is also 300m
- Velocity = Displacement/Time = 300m/150s = 2 m/s (in the direction from A to B)
From A to C:
- Distance from A to C = 300m (A to B) + 100m (B to C) = 400m
- Time taken = 2 minutes 30 seconds (A to B) + 1 minute (B to C) = 210 seconds
- Speed = Total Distance/Total Time = 400m/210s ≈ 1.90 m/s
- Velocity is a vector quantity, and for the total journey from A to C, the displacement is 100m (from A to C)
- Velocity = Displacement/Total Time = 100m/210s ≈ 0.476 m/s (in the direction from A to C)
Explanation:
- Joseph's average speed from A to B is 2 m/s, which means he covers 2 meters in one second on average.
- Joseph's average speed from A to C is slightly lower at 1.90 m/s, considering the additional distance covered in the same total time.
- The velocity from A to B and from A to C are the same in magnitude (2 m/s and 1.90 m/s, respectively) as they represent the rate of change of position. However, the direction of the velocity vector differs based on the journey.
Community Answer
Joseph jogs from one end A to the other end B of a straight 300m road ...
A to b=300/150=2a to c=400/210=40/21.
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Joseph jogs from one end A to the other end B of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C?
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Joseph jogs from one end A to the other end B of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Joseph jogs from one end A to the other end B of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Joseph jogs from one end A to the other end B of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C?.
Joseph jogs from one end A to the other end B of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Joseph jogs from one end A to the other end B of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Joseph jogs from one end A to the other end B of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C?.
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