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When electricity is passed through aqueous solution of aluminium chloride, 13.5 g of Al are deposited. The number of faradays of electricity passed must be
  • a)
    2.0
  • b)
    1.5
  • c)
    1.0
  • d)
    0.5
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
When electricity is passed through aqueous solution of aluminium chlor...
Given data:
- Mass of Al deposited = 13.5 g

Calculating the number of moles of Al deposited:
- The molar mass of Al is 27 g/mol.
- Number of moles of Al deposited = 13.5 g / 27 g/mol = 0.5 mol

Understanding Faraday's law of electrolysis:
- 1 Faraday of electricity is the charge required to deposit 1 mole of a substance during electrolysis.
- The charge carried by 1 mole of electrons is equivalent to 1 Faraday.

Calculating the number of faradays of electricity passed:
- Since 0.5 mol of Al is deposited, 0.5 Faraday of electricity is passed.
- Therefore, the correct answer is option B) 1.5.
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When electricity is passed through aqueous solution of aluminium chloride, 13.5 g of Al are deposited. The number of faradays of electricity passed must bea)2.0b)1.5c)1.0d)0.5Correct answer is option 'B'. Can you explain this answer?
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