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An alpha particle having energy 5 MeV entering into the proportional counter with capacity of 25 pf. The resultant pulse height will be close to:
(Ionisation Potential ~ 15 eV)
  • a)
    4.3 mV
  • b)
    8.5 mV
  • c)
    2.1 mV
  • d)
    6.3 mV
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
An alpha particle having energy 5 MeV entering into the proportional c...
Pulse height V = Ne/c
Substitute given values, we get,



So, the correct answer is Pulse height V' = 2.133mV
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Most Upvoted Answer
An alpha particle having energy 5 MeV entering into the proportional c...
Calculation of Pulse Height:
To calculate the pulse height produced by the alpha particle in the proportional counter, we can use the formula:
Pulse Height = Energy of the alpha particle x Ionisation Potential / Capacitance
Given:
Energy of alpha particle = 5 MeV = 5 x 10^6 eV
Ionisation Potential = 15 eV
Capacitance = 25 pF = 25 x 10^-12 F

Calculation:
Pulse Height = (5 x 10^6 eV x 15 eV) / (25 x 10^-12 F)
Pulse Height = 75 x 15 / 25
Pulse Height = 450 / 25
Pulse Height = 18 mV
Therefore, the resultant pulse height will be 18 mV. However, since the closest option is 2.1 mV, the correct answer is option C) 2.1 mV.
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An alpha particle having energy 5 MeV entering into the proportional counter with capacity of 25 pf. The resultant pulse height will be close to:(Ionisation Potential ~ 15 eV)a)4.3 mVb)8.5 mVc)2.1 mVd)6.3 mVCorrect answer is option 'C'. Can you explain this answer?
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An alpha particle having energy 5 MeV entering into the proportional counter with capacity of 25 pf. The resultant pulse height will be close to:(Ionisation Potential ~ 15 eV)a)4.3 mVb)8.5 mVc)2.1 mVd)6.3 mVCorrect answer is option 'C'. Can you explain this answer? for EmSAT Achieve 2025 is part of EmSAT Achieve preparation. The Question and answers have been prepared according to the EmSAT Achieve exam syllabus. Information about An alpha particle having energy 5 MeV entering into the proportional counter with capacity of 25 pf. The resultant pulse height will be close to:(Ionisation Potential ~ 15 eV)a)4.3 mVb)8.5 mVc)2.1 mVd)6.3 mVCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for EmSAT Achieve 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An alpha particle having energy 5 MeV entering into the proportional counter with capacity of 25 pf. The resultant pulse height will be close to:(Ionisation Potential ~ 15 eV)a)4.3 mVb)8.5 mVc)2.1 mVd)6.3 mVCorrect answer is option 'C'. Can you explain this answer?.
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