Coefficient of mean deviation about mean of the first 9 natural number...
1,2,3,4,5,6,7,8,9
Σx = 1+2+3+4+5+6+7+8+9 = 45
mean = 45/9 = 5
absolute deviations from the mean:
1-5, 2-5 ,... 9-5 in absolute value
4,3,2,1,0,1,2,3,4
add the absolute deviations and divide by 9
Absolute deviations from the mean = 20/9
divide by the mean = (20/9) / 5 = 20/45 = 4/9 = 0.4444
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Coefficient of mean deviation about mean of the first 9 natural number...
Coefficient of Mean Deviation:
The mean deviation is a measure of variability that represents the average absolute difference of each observation from the mean of the data set. The coefficient of mean deviation is the ratio of the mean deviation to the mean of the data set.
Formula:
Coefficient of Mean Deviation (CMD) = Mean Deviation / Mean
Finding Mean:
The first step is to find the mean of the first 9 natural numbers.
Mean = (1+2+3+4+5+6+7+8+9)/9
Mean = 5
Finding Deviations:
The next step is to find the deviations of each observation from the mean.
Deviations = |Observation - Mean|
Deviations = |1-5|, |2-5|, |3-5|, |4-5|, |5-5|, |6-5|, |7-5|, |8-5|, |9-5|
Deviations = 4, 3, 2, 1, 0, 1, 2, 3, 4
Finding Mean Deviation:
The mean deviation is the average of these deviations.
Mean Deviation = (4+3+2+1+0+1+2+3+4)/9
Mean Deviation = 2
Finding Coefficient of Mean Deviation:
The coefficient of mean deviation is the ratio of the mean deviation to the mean.
Coefficient of Mean Deviation (CMD) = Mean Deviation / Mean
CMD = 2/5
CMD = 400/9
Therefore, the correct option is C) 400/9.
Coefficient of mean deviation about mean of the first 9 natural number...