An optically pure organic compound has specific rotation of +40o. Determine the optical purity of the sample that exhibits specific rotation of +32°.?

Question

Answer

Calculation of Optical Purity

Given:
- Specific rotation of optically pure compound = +40°
- Specific rotation of sample = +32°

Formula:
- Optical purity (%) = (Observed specific rotation / Specific rotation of enantiomer) x 100

Calculation:
- Optical purity (%) = (32 / 40) x 100 = 80%
Therefore, the optical purity of the sample is 80%.

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