A straight line having a slope of -ΔUo / R is obtained in a plot ...
Explanation:
The slope of a straight line in a plot between two variables can provide important information about the relationship between those variables. In this case, we are given that the slope of the line is -Uo / R. Let's explore what this means for each of the given options.
Option A: In (Kp) versus T
- This option involves plotting the natural logarithm of the equilibrium constant for a reaction (Kp) against temperature (T).
- The slope of the line would be related to the activation energy of the reaction, not -Uo / R.
Option B: In (Kc) versus T
- This option is similar to Option A, but uses the equilibrium constant expressed in terms of molar concentrations (Kc).
- Again, the slope of the line would not be related to -Uo / R.
Option C: In (Kp) versus 1/T
- This option involves plotting the natural logarithm of Kp against the inverse of temperature.
- The slope of the line would be related to the enthalpy change of the reaction, not -Uo / R.
Option D: In (Kc) versus 1/T
- This option is similar to Option C, but uses Kc instead of Kp.
- The slope of the line would be related to -Uo / R, which is the ratio of the activation energy to the gas constant.
Conclusion:
Therefore, the correct answer is Option D, as it is the only option where the slope of the line is related to -Uo / R.
A straight line having a slope of -ΔUo / R is obtained in a plot ...
According to arhenius equn..K=Ae^-E/RTTaking natural logarithmic of both sidelnk=lnA-E/RTOr lnkc=lnA-deltaU/RTSo graph b/w ln(kc) and 1/T gives Slope =-deltaU/R and intecept =lnA