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An aeroplane is moving with horizontal velocity u at height h. The velocity of a packet dropped from it on the earth's surface will be (g is acceleration due to gravity)
- a)√u2+2gh
- b)√2gh
- c)2 gh
- d)√u2-2gh
Correct answer is option 'A'. Can you explain this answer?
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An aeroplane is moving with horizontal velocity u at height h. The vel...
Explanation:
- The vertical motion of the packet is independent of the horizontal motion of the airplane.
- When the packet is dropped, it has zero initial velocity in the vertical direction.
- The only force acting on the packet in the vertical direction is gravity.
- The acceleration due to gravity is denoted by 'g' and it acts downwards.
- The equation for the motion of the packet in the vertical direction is:
h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity, and t is the time taken to reach the ground.
- The time taken for the packet to reach the ground can be found using the equation:
h = (1/2)gt^2
t = √(2h/g)
- The horizontal velocity of the airplane does not affect the vertical motion of the packet.
- The horizontal velocity of the packet when it reaches the ground is the same as the horizontal velocity of the airplane.
- Therefore, the horizontal velocity of the packet when it reaches the ground is 'u'.
- The total velocity of the packet when it reaches the ground is the vector sum of its horizontal and vertical velocities.
- Using Pythagoras theorem, the total velocity of the packet when it reaches the ground is:
V = √(u^2 + (2gh)^2)
- Therefore, the velocity of the packet dropped from the airplane on the earth's surface is √(u^2 + 2gh).
Thus, the correct answer is option 'A'.
- The vertical motion of the packet is independent of the horizontal motion of the airplane.
- When the packet is dropped, it has zero initial velocity in the vertical direction.
- The only force acting on the packet in the vertical direction is gravity.
- The acceleration due to gravity is denoted by 'g' and it acts downwards.
- The equation for the motion of the packet in the vertical direction is:
h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity, and t is the time taken to reach the ground.
- The time taken for the packet to reach the ground can be found using the equation:
h = (1/2)gt^2
t = √(2h/g)
- The horizontal velocity of the airplane does not affect the vertical motion of the packet.
- The horizontal velocity of the packet when it reaches the ground is the same as the horizontal velocity of the airplane.
- Therefore, the horizontal velocity of the packet when it reaches the ground is 'u'.
- The total velocity of the packet when it reaches the ground is the vector sum of its horizontal and vertical velocities.
- Using Pythagoras theorem, the total velocity of the packet when it reaches the ground is:
V = √(u^2 + (2gh)^2)
- Therefore, the velocity of the packet dropped from the airplane on the earth's surface is √(u^2 + 2gh).
Thus, the correct answer is option 'A'.
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An aeroplane is moving with horizontal velocity u at height h. The velocity of a packet dropped from it on the earths surface will be (g is acceleration due to gravity)a)√u2+2ghb)√2ghc)2 ghd)√u2-2ghCorrect answer is option 'A'. Can you explain this answer?
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An aeroplane is moving with horizontal velocity u at height h. The velocity of a packet dropped from it on the earths surface will be (g is acceleration due to gravity)a)√u2+2ghb)√2ghc)2 ghd)√u2-2ghCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An aeroplane is moving with horizontal velocity u at height h. The velocity of a packet dropped from it on the earths surface will be (g is acceleration due to gravity)a)√u2+2ghb)√2ghc)2 ghd)√u2-2ghCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An aeroplane is moving with horizontal velocity u at height h. The velocity of a packet dropped from it on the earths surface will be (g is acceleration due to gravity)a)√u2+2ghb)√2ghc)2 ghd)√u2-2ghCorrect answer is option 'A'. Can you explain this answer?.
An aeroplane is moving with horizontal velocity u at height h. The velocity of a packet dropped from it on the earths surface will be (g is acceleration due to gravity)a)√u2+2ghb)√2ghc)2 ghd)√u2-2ghCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An aeroplane is moving with horizontal velocity u at height h. The velocity of a packet dropped from it on the earths surface will be (g is acceleration due to gravity)a)√u2+2ghb)√2ghc)2 ghd)√u2-2ghCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An aeroplane is moving with horizontal velocity u at height h. The velocity of a packet dropped from it on the earths surface will be (g is acceleration due to gravity)a)√u2+2ghb)√2ghc)2 ghd)√u2-2ghCorrect answer is option 'A'. Can you explain this answer?.
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