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An aeroplane is moving with horizontal velocity u at height h. The velocity of a packet dropped from it on the earth's surface will be (g is acceleration due to gravity)
  • a)
    √u2+2gh
  • b)
    √2gh
  • c)
    2 gh
  • d)
    √u2-2gh
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
An aeroplane is moving with horizontal velocity u at height h. The vel...
Initially, the pocket has an only horizontal velocity equal to u
When it reaches the ground it has horizontal velocity u and vertical velocity 2gh√
Therefore resultant velocity =√u^2+2gh
Hence A is the correct answer.
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Most Upvoted Answer
An aeroplane is moving with horizontal velocity u at height h. The vel...
The velocity of the packet dropped from the airplane can be determined using the equation of motion:

v^2 = u^2 + 2gh

where v is the final velocity of the packet, u is the horizontal velocity of the airplane, g is the acceleration due to gravity, and h is the height from which the packet is dropped.

Since the airplane is moving horizontally, the initial vertical velocity of the packet is zero. Therefore, the final velocity of the packet will only have a horizontal component, given by:

v = u

So, the velocity of the packet dropped from the airplane on the Earth's surface will be equal to the horizontal velocity of the airplane, u.
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