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(iv) 2x2 – x +1/8 = 0

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(iv) 2x2 – x +1/8 = 0Read more at: https://edurev.in/t/119850/NCERT-So...
**Given Equation:**
2x^2 - x + 1/8 = 0
**Explanation:**
**1. Quadratic Equation:**
- The given equation is a quadratic equation in the form ax^2 + bx + c = 0.
- Here, a = 2, b = -1, and c = 1/8.
**2. Find Discriminant:**
- Calculate the discriminant using the formula Δ = b^2 - 4ac.
- In this case, Δ = (-1)^2 - 4*2*(1/8) = 1 - 1 = 0.
**3. Nature of Roots:**
- Since the discriminant is zero, the roots of the equation will be real and equal.
- The equation will have one solution.
**4. Find the Roots:**
- Use the formula x = (-b ± √Δ) / 2a to find the roots.
- Substitute the values of a, b, and Δ into the formula to find the roots.
**5. Simplify the Equation:**
- Solve the equation to find the value of x by simplifying the expression.
**6. Conclusion:**
- After finding the roots of the given quadratic equation, you can conclude whether the equation has real roots or not based on the nature of the discriminant.
By following these steps, you will be able to understand and solve the given quadratic equation effectively.
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(iv) 2x2 – x +1/8 = 0Read more at: https://edurev.in/t/119850/NCERT-Solutions-for-Class-10-Maths-Chapter-4-Quadratic-Equations-Exercise-4.1? I have a doubt in this question cant able to understand?
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