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Let y1(x) = 1 + x and y2(x) = ex be two solutions of y”(x) + p(x)y’(x) + Q(x)y(x) = 0 then the set of initial conditions for which the above differential equation has No solution is .a)y(1)= 2, y’(1) = 1b)y(0) =1, y’(0) = 2c)y(0)= 2, y’(0) = 1d)None of theseCorrect answer is option 'C'. Can you explain this answer? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared
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the Mathematics exam syllabus. Information about Let y1(x) = 1 + x and y2(x) = ex be two solutions of y”(x) + p(x)y’(x) + Q(x)y(x) = 0 then the set of initial conditions for which the above differential equation has No solution is .a)y(1)= 2, y’(1) = 1b)y(0) =1, y’(0) = 2c)y(0)= 2, y’(0) = 1d)None of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mathematics 2024 Exam.
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Here you can find the meaning of Let y1(x) = 1 + x and y2(x) = ex be two solutions of y”(x) + p(x)y’(x) + Q(x)y(x) = 0 then the set of initial conditions for which the above differential equation has No solution is .a)y(1)= 2, y’(1) = 1b)y(0) =1, y’(0) = 2c)y(0)= 2, y’(0) = 1d)None of theseCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Let y1(x) = 1 + x and y2(x) = ex be two solutions of y”(x) + p(x)y’(x) + Q(x)y(x) = 0 then the set of initial conditions for which the above differential equation has No solution is .a)y(1)= 2, y’(1) = 1b)y(0) =1, y’(0) = 2c)y(0)= 2, y’(0) = 1d)None of theseCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Let y1(x) = 1 + x and y2(x) = ex be two solutions of y”(x) + p(x)y’(x) + Q(x)y(x) = 0 then the set of initial conditions for which the above differential equation has No solution is .a)y(1)= 2, y’(1) = 1b)y(0) =1, y’(0) = 2c)y(0)= 2, y’(0) = 1d)None of theseCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Let y1(x) = 1 + x and y2(x) = ex be two solutions of y”(x) + p(x)y’(x) + Q(x)y(x) = 0 then the set of initial conditions for which the above differential equation has No solution is .a)y(1)= 2, y’(1) = 1b)y(0) =1, y’(0) = 2c)y(0)= 2, y’(0) = 1d)None of theseCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Let y1(x) = 1 + x and y2(x) = ex be two solutions of y”(x) + p(x)y’(x) + Q(x)y(x) = 0 then the set of initial conditions for which the above differential equation has No solution is .a)y(1)= 2, y’(1) = 1b)y(0) =1, y’(0) = 2c)y(0)= 2, y’(0) = 1d)None of theseCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Mathematics tests.