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If n numbers are inserted between 15 and 60 such that the ratio of the first to the last is 1 : 3, then the value of n is:
  • a)
    3
  • b)
    4
  • c)
    11
  • d)
    15
Correct answer is option 'C'. Can you explain this answer?
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If n numbers are inserted between 15 and 60 such that the ratio of the...

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If n numbers are inserted between 15 and 60 such that the ratio of the...
Let the series be a,a+d,a+2d,.......,a+(n)d,b ther
efore given that a+d÷a+nd=1÷3 then,3a+3d
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If n numbers are inserted between 15 and 60 such that the ratio of the...
Given Information:
- The ratio of the first number to the last number is 1:3.
- The numbers are inserted between 15 and 60.

Solution:

Step 1: Finding the total number of numbers inserted
Let the number of numbers inserted be n.
The total ratio parts = 1 + 3 = 4
The difference between 60 and 15 = 60 - 15 = 45
Each part = 45 / 4 = 11.25
Therefore, the numbers inserted between 15 and 60 = 11 * 11.25 = 123.75

Step 2: Finding the value of n
To find the value of n, we need to consider that the numbers inserted are integers.
Since we can't have fractional numbers, we need to round down the decimal value of 123.75 to the nearest integer, which is 123.
Therefore, the value of n = 123.
Hence, the correct answer is option C which is 11.
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If n numbers are inserted between 15 and 60 such that the ratio of the first to the last is 1 : 3, then the value of n is:a)3b)4c)11d)15Correct answer is option 'C'. Can you explain this answer?
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