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The number of turs of primary and secondary coils of a transformer are 5 and 10 respectively and mutual inductance of the transformer is 25 H. Now, number of turns in primary and secondary are made 10 and 5 respectuvely. Mutual inductance of transformer will be
  • a)
    25 H
  • b)
    12.5 H
  • c)
    50 H
  • d)
    6.25 H
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The number of turs of primary and secondary coils of a transformer are...
Explanation:

Given Data:
- Number of turns in primary coil (N1) = 5
- Number of turns in secondary coil (N2) = 10
- Mutual inductance of the transformer (M) = 25 H

Formula:
- Mutual inductance (M) of a transformer is given by the formula:
M = k * sqrt(N1 * N2), where k is a constant

Calculating the constant k:
Using the given data, we can calculate the constant k:
25 = k * sqrt(5 * 10)
25 = k * sqrt(50)
k = 25 / sqrt(50)
k = 25 / 7.07
k ≈ 3.54

Calculating new mutual inductance:
- Now, the number of turns in the primary coil (N1) = 10
- Number of turns in the secondary coil (N2) = 5
- Using the formula for mutual inductance:
M = k * sqrt(N1 * N2)
M = 3.54 * sqrt(10 * 5)
M = 3.54 * sqrt(50)
M = 3.54 * 7.07
M ≈ 25 H
Therefore, the mutual inductance of the transformer will still be 25 H even after changing the number of turns in the primary and secondary coils. Hence, the correct answer is option 'a) 25 H'.
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