Explanation:

The hybridization state in triangle bipyramidal CH5 is SP2.

- Hybridization: Hybridization is the process of mixing atomic orbitals to form new hybrid orbitals that have different properties from the original orbitals. The hybridization state of an atom is determined by the number of hybrid orbitals it forms.

- Triangle bipyramidal geometry: Triangle bipyramidal geometry is a type of molecular geometry where a central atom is surrounded by five ligands. The arrangement of these ligands is such that there are three atoms in the equatorial plane and two atoms in the axial positions.

- CH5: CH5 is a hypothetical molecule that is not stable. However, it can be used as an example to understand the hybridization state in triangle bipyramidal geometry.

- Hybridization state in CH5: In CH5, the central carbon atom is surrounded by five hydrogen atoms. The carbon atom has four valence electrons, which means it needs four hybrid orbitals to form four covalent bonds with the hydrogen atoms.

- To form four hybrid orbitals, the carbon atom undergoes sp2 hybridization. This means that one s orbital and two p orbitals of the carbon atom are mixed to form three sp2 hybrid orbitals.

- These sp2 hybrid orbitals form sigma bonds with the hydrogen atoms in the equatorial plane. The remaining two p orbitals of the carbon atom form pi bonds with the hydrogen atoms in the axial positions.

- Therefore, the hybridization state in triangle bipyramidal CH5 is sp2.

- Note: It is important to note that CH5 is not a stable molecule, and the actual hybridization state in triangle bipyramidal molecules may vary depending on the specific molecule.