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 A body moves under a force such that momentum of the body at any instant showimage (3). What is the rate of work done by the force?
  • a)
  • b)
  • c)
  • d)
    zero
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A body moves under a force such that momentum of the body at any insta...
P = p Cos(t) i + p Sin(t) j
dP/dt = -p Sin(t) j + p Cos(t) i
Work done, W = P2/2m
Rate of work done = d/dt(P2/2m)
= 2P/2m x dP/dt
= P/m x dP/dt
= -p2.Sin(t).Cos(t) + p2.Sin(t).Cos(t)
=> Rate of work done = 0
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Most Upvoted Answer
A body moves under a force such that momentum of the body at any insta...
P = p Cos(t) i + p Sin(t) j
dP/dt = -p Sin(t) j + p Cos(t) i
Work done, W = P2/2m
Rate of work done = d/dt(P2/2m)
= 2P/2m x dP/dt
= P/m x dP/dt
= -p2.Sin(t).Cos(t) + p2.Sin(t).Cos(t)
=> Rate of work done = 0
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Community Answer
A body moves under a force such that momentum of the body at any insta...
Zero yr ,,,just see the angle its 90

so no work done then how can u calculate the power (rate of work done)
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