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What happens when sncl2 solution is treated with strong solution of naoh?
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What happens when sncl2 solution is treated with strong solution of na...
Reaction of SnCl2 solution with strong NaOH solution
When a solution of SnCl2 is treated with a strong solution of NaOH, a series of chemical reactions occur which can be explained as follows:

Formation of Sn(OH)2
- SnCl2 reacts with NaOH to form Sn(OH)2, a white precipitate.
- The balanced chemical equation for this reaction is: SnCl2 + 2NaOH → Sn(OH)2 + 2NaCl

Formation of Sn(OH)4
- The Sn(OH)2 precipitate further reacts with excess NaOH to form Sn(OH)4, a gelatinous precipitate.
- The balanced chemical equation for this reaction is: Sn(OH)2 + 2NaOH → Sn(OH)4 + 2Na

Formation of SnO2
- Sn(OH)4 dehydrates upon heating to form SnO2, a brown solid.
- The balanced chemical equation for this reaction is: Sn(OH)4 → SnO2 + 2H2O

Overall reaction
- The overall reaction can be represented as: SnCl2 + 4NaOH → SnO2 + 2Na2SnO3 + 2NaCl + 2H2O
These reactions demonstrate the complex chemistry involved when SnCl2 solution is treated with a strong NaOH solution. The formation of different precipitates and solids highlights the versatility of tin compounds in various chemical reactions.
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What happens when sncl2 solution is treated with strong solution of naoh?
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