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The sum of the digits of a two digit number is 8. If the digits are reversed, the number is decreased by 54. Find the number.?
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The sum of the digits of a two digit number is 8. If the digits are re...
Given Information:
- The sum of the digits of a two-digit number is 8.
- When the digits are reversed, the number is decreased by 54.

Let's solve the problem step by step:

Step 1: Setting up the equation
- Let the tens digit be x and the units digit be y.
- The number can be represented as 10x + y.
- According to the first condition, the sum of the digits is 8: x + y = 8.
- According to the second condition, when the digits are reversed, the number is decreased by 54: 10y + x = 10x + y - 54.

Step 2: Solving the equations
- From the first equation x + y = 8, we can rewrite it as y = 8 - x.
- Substituting y = 8 - x into the second equation gives us 10(8 - x) + x = 10x + (8 - x) - 54.
- Simplifying the equation: 80 - 10x + x = 10x + 8 - x - 54.
- Further simplifying: 80 - 9x = 9.
- Solving for x: x = 8.
- Substituting x = 8 back into y = 8 - x, we get y = 8 - 8 = 0.

Step 3: Finding the number
- The original number is 10x + y = 10(8) + 0 = 80.
Therefore, the two-digit number is 80.
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The sum of the digits of a two digit number is 8. If the digits are reversed, the number is decreased by 54. Find the number.?
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