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The difference of the digits of a two digit number is 4 and the sum of the number and the number obtained by reversing the two digits is 66 find the numbers?
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The difference of the digits of a two digit number is 4 and the sum of...
Given Information:
- The difference of the digits of a two-digit number is 4.
- The sum of the number and the number obtained by reversing the two digits is 66.
Step-by-Step Solution:
Let's assume the two-digit number is represented as 10a + b, where a and b are the digits.
1. Formulating the equation based on the given information:
According to the given information:
- The difference of the digits is 4: a - b = 4
- The sum of the number and the number obtained by reversing the digits is 66: 10a + b + 10b + a = 66
2. Solving the equations:
From the first equation, we get a = b + 4
Substitute the value of a in the second equation:
10(b+4) + b + 10b + (b+4) = 66
Simplify the equation: 12b + 14 = 66
12b = 52
b = 52/12
b = 4 (approx.)
Substitute the value of b in a = b + 4:
a = 4 + 4
a = 8
3. Finding the two-digit numbers:
The two-digit number is 10a + b = 10(8) + 4 = 84
The number obtained by reversing the digits is 10b + a = 10(4) + 8 = 48
Therefore, the numbers are 84 and 48.
Conclusion:
The two-digit numbers that satisfy the given conditions are 84 and 48.
- The difference of the digits of a two-digit number is 4.
- The sum of the number and the number obtained by reversing the two digits is 66.
Step-by-Step Solution:
Let's assume the two-digit number is represented as 10a + b, where a and b are the digits.
1. Formulating the equation based on the given information:
According to the given information:
- The difference of the digits is 4: a - b = 4
- The sum of the number and the number obtained by reversing the digits is 66: 10a + b + 10b + a = 66
2. Solving the equations:
From the first equation, we get a = b + 4
Substitute the value of a in the second equation:
10(b+4) + b + 10b + (b+4) = 66
Simplify the equation: 12b + 14 = 66
12b = 52
b = 52/12
b = 4 (approx.)
Substitute the value of b in a = b + 4:
a = 4 + 4
a = 8
3. Finding the two-digit numbers:
The two-digit number is 10a + b = 10(8) + 4 = 84
The number obtained by reversing the digits is 10b + a = 10(4) + 8 = 48
Therefore, the numbers are 84 and 48.
Conclusion:
The two-digit numbers that satisfy the given conditions are 84 and 48.
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The difference of the digits of a two digit number is 4 and the sum of the number and the number obtained by reversing the two digits is 66 find the numbers?
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The difference of the digits of a two digit number is 4 and the sum of the number and the number obtained by reversing the two digits is 66 find the numbers? for SSC CHSL 2025 is part of SSC CHSL preparation. The Question and answers have been prepared according to the SSC CHSL exam syllabus. Information about The difference of the digits of a two digit number is 4 and the sum of the number and the number obtained by reversing the two digits is 66 find the numbers? covers all topics & solutions for SSC CHSL 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The difference of the digits of a two digit number is 4 and the sum of the number and the number obtained by reversing the two digits is 66 find the numbers?.
The difference of the digits of a two digit number is 4 and the sum of the number and the number obtained by reversing the two digits is 66 find the numbers? for SSC CHSL 2025 is part of SSC CHSL preparation. The Question and answers have been prepared according to the SSC CHSL exam syllabus. Information about The difference of the digits of a two digit number is 4 and the sum of the number and the number obtained by reversing the two digits is 66 find the numbers? covers all topics & solutions for SSC CHSL 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The difference of the digits of a two digit number is 4 and the sum of the number and the number obtained by reversing the two digits is 66 find the numbers?.
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