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When (3)^1989 is divided by 7 the reminder will be?
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When (3)^1989 is divided by 7 the reminder will be?
Explanation:
To find the remainder when \(3^{1989}\) is divided by 7, we can use the concept of modular arithmetic.

Modular Arithmetic:
Modular arithmetic is a system of arithmetic for integers, where numbers "wrap around" upon reaching a certain value called the modulus.

Using Fermat's Little Theorem:
Fermat's Little Theorem states that if p is a prime number, then for any integer a not divisible by p, \(a^{p-1} \equiv 1 \pmod p\).

Applying Fermat's Little Theorem:
In this case, the modulus is 7, which is a prime number. Therefore, we can apply Fermat's Little Theorem to simplify the calculation.
\(3^{1989} \equiv 3^{1989 \mod 6} \pmod 7\)
\(1989 \mod 6 = 3\)
\(3^{1989} \equiv 3^3 \equiv 27 \equiv 6 \pmod 7\)

Final Answer:
When \(3^{1989}\) is divided by 7, the remainder is 6.
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When (3)^1989 is divided by 7 the reminder will be?
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