The ground state term symbols for high spin d5s1 and d5 configurations, respectively are:a)3S and 6Sb)6P and 3Sc)7S and 6Sd)7P and 6SCorrect answer is option 'C'. Can you explain this answer?

Question

Answer

Explanation:

For d5s1 configuration, since s=1/2, the total spin can range from 5/2 to 1/2. The total angular momentum can range from 4 to 0.

For d5 configuration, since there are 5 electrons with s=1/2, the total spin can range from 5/2 to 1/2. The total angular momentum can range from 5 to 0.

To determine the ground state term symbol, we need to find the combination of spin and angular momentum that gives the lowest energy.

For d5s1 configuration:

- The lowest spin state is when all electrons are paired, giving a total spin of S=0.
- The lowest angular momentum state is when all electrons occupy the same d orbital, giving a total angular momentum of L=2.
- The ground state term symbol is then 3S, since S=0 and L=2.

For d5 configuration:

- The lowest spin state is when all electrons are paired, giving a total spin of S=0.
- The lowest angular momentum state is when all electrons occupy the same d orbital, giving a total angular momentum of L=5.
- The ground state term symbol is then 6S, since S=0 and L=5.

Therefore, the correct answer is option C, 7S and 6S.

Answer

For d5 s¹ , ML = 0 = S state and S = 6/2=3 , 2S+1 = 7 , hence ground state term symbol is 7S . For d5 , ML is same as o i.e. S state and S = 5/2 , 2S+1 = 6 , hence term symbol is 6S

Answer

Here's the solution to your question:

Hence Option (C) is correct

For the Practice sheet on Coordination Chemistry click on link given below:

Coordination Compounds (Advanced) - Practice Sheet, Class 12, Chemistry

https://edurev.in/studytube/coordination-compounds--advanced--practice-sheet--/10204338-296c-4e0c-a89b-5c3c5673b020_p

Answer

C

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