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When BrO3 ion reacts with Br ion in acid solution Br2 is liberated. The eq. weight of KBrO3 in this reaction is:
  • a)
    M/8
  • b)
    M/3
  • c)
    M/5
  • d)
    M/6
Correct answer is option 'C'. Can you explain this answer?
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When BrO3– ion reacts with Br– ion in acid solution Br2 is...
 
10e + 2Br5+ → Br02
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When BrO3– ion reacts with Br– ion in acid solution Br2 is...
Answer:

To determine the equivalent weight of KBrO3 in the given reaction, we need to analyze the stoichiometry of the reaction and consider the valence factors of the ions involved.

The reaction given is:
BrO3- + 5Br- + 6H+ → 3Br2 + 3H2O

From the reaction, we can see that 1 mole of BrO3- reacts with 5 moles of Br- to produce 3 moles of Br2. This indicates that the valence factor of BrO3- is 5.

The equivalent weight of a compound is defined as the molecular weight divided by the valence factor. In this case, the molecular weight of KBrO3 is M.

Therefore, the equivalent weight of KBrO3 = M/5

So, the correct answer is option C) M/5.
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When BrO3– ion reacts with Br– ion in acid solution Br2 is...
Due to nfactor. 5
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