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Given EºCr3+/Cr = – 0.72 V, EºFe2+/Fe= – 0.42 V. The potential for the cell Cr |Cr3+ (0.1 M)| |Fe2+ (0.01 M) | Fe is - [AIEEE 2008]
- a)0.339 V
- b)– 0.339 V
- c)– 0.26 V
- d)0.26 V
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Given EºCr3+/Cr = –0.72 V, EºFe2+/Fe= –0.42 V.Th...
The correct answer is option D
Cr∣Cr3+(0.1 M)∣∣Fe2+(0.01 M)∣Fe
Oxidation half-cell
Cr→Cr3++3e−]×2
Reduction half-cell
Fe2++2e−→Fe]×3
Net cell reaction
2Cr+3Fe2+→2Cr3++3Fe, n=6
E∘cell= E∘oxi+E∘red
=0.72−0.42 = 0.30 V
Cr∣Cr3+(0.1 M)∣∣Fe2+(0.01 M)∣Fe
Oxidation half-cell
Cr→Cr3++3e−]×2
Reduction half-cell
Fe2++2e−→Fe]×3
Net cell reaction
2Cr+3Fe2+→2Cr3++3Fe, n=6
E∘cell= E∘oxi+E∘red
=0.72−0.42 = 0.30 V
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Given EºCr3+/Cr = –0.72 V, EºFe2+/Fe= –0.42 V.Th...
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Given EºCr3+/Cr = –0.72 V, EºFe2+/Fe= –0.42 V.The potential for the cell Cr |Cr3+(0.1 M)| |Fe2+(0.01 M) | Fe is - [AIEEE 2008]a)0.339 Vb)–0.339 Vc)–0.26 Vd)0.26 VCorrect answer is option 'D'. Can you explain this answer?
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Given EºCr3+/Cr = –0.72 V, EºFe2+/Fe= –0.42 V.The potential for the cell Cr |Cr3+(0.1 M)| |Fe2+(0.01 M) | Fe is - [AIEEE 2008]a)0.339 Vb)–0.339 Vc)–0.26 Vd)0.26 VCorrect answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Given EºCr3+/Cr = –0.72 V, EºFe2+/Fe= –0.42 V.The potential for the cell Cr |Cr3+(0.1 M)| |Fe2+(0.01 M) | Fe is - [AIEEE 2008]a)0.339 Vb)–0.339 Vc)–0.26 Vd)0.26 VCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given EºCr3+/Cr = –0.72 V, EºFe2+/Fe= –0.42 V.The potential for the cell Cr |Cr3+(0.1 M)| |Fe2+(0.01 M) | Fe is - [AIEEE 2008]a)0.339 Vb)–0.339 Vc)–0.26 Vd)0.26 VCorrect answer is option 'D'. Can you explain this answer?.
Given EºCr3+/Cr = –0.72 V, EºFe2+/Fe= –0.42 V.The potential for the cell Cr |Cr3+(0.1 M)| |Fe2+(0.01 M) | Fe is - [AIEEE 2008]a)0.339 Vb)–0.339 Vc)–0.26 Vd)0.26 VCorrect answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Given EºCr3+/Cr = –0.72 V, EºFe2+/Fe= –0.42 V.The potential for the cell Cr |Cr3+(0.1 M)| |Fe2+(0.01 M) | Fe is - [AIEEE 2008]a)0.339 Vb)–0.339 Vc)–0.26 Vd)0.26 VCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given EºCr3+/Cr = –0.72 V, EºFe2+/Fe= –0.42 V.The potential for the cell Cr |Cr3+(0.1 M)| |Fe2+(0.01 M) | Fe is - [AIEEE 2008]a)0.339 Vb)–0.339 Vc)–0.26 Vd)0.26 VCorrect answer is option 'D'. Can you explain this answer?.
Solutions for Given EºCr3+/Cr = –0.72 V, EºFe2+/Fe= –0.42 V.The potential for the cell Cr |Cr3+(0.1 M)| |Fe2+(0.01 M) | Fe is - [AIEEE 2008]a)0.339 Vb)–0.339 Vc)–0.26 Vd)0.26 VCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Given EºCr3+/Cr = –0.72 V, EºFe2+/Fe= –0.42 V.The potential for the cell Cr |Cr3+(0.1 M)| |Fe2+(0.01 M) | Fe is - [AIEEE 2008]a)0.339 Vb)–0.339 Vc)–0.26 Vd)0.26 VCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Given EºCr3+/Cr = –0.72 V, EºFe2+/Fe= –0.42 V.The potential for the cell Cr |Cr3+(0.1 M)| |Fe2+(0.01 M) | Fe is - [AIEEE 2008]a)0.339 Vb)–0.339 Vc)–0.26 Vd)0.26 VCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Given EºCr3+/Cr = –0.72 V, EºFe2+/Fe= –0.42 V.The potential for the cell Cr |Cr3+(0.1 M)| |Fe2+(0.01 M) | Fe is - [AIEEE 2008]a)0.339 Vb)–0.339 Vc)–0.26 Vd)0.26 VCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Given EºCr3+/Cr = –0.72 V, EºFe2+/Fe= –0.42 V.The potential for the cell Cr |Cr3+(0.1 M)| |Fe2+(0.01 M) | Fe is - [AIEEE 2008]a)0.339 Vb)–0.339 Vc)–0.26 Vd)0.26 VCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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