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The winding of a motor has a resistance of 80 ohms at 15°C. Find its resistance at 50° C. the temperature co-efficient of resistance is 0.004/°C
- a)60.57Ω
- b)75.47Ω
- c)90.56Ω
- d)80.0Ω
Correct answer is option 'C'. Can you explain this answer?
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The winding of a motor has a resistance of 80 ohms at 15°C. Find ...
°C. What will be its resistance at 40°C if the temperature coefficient of resistance of the winding material is 0.004/°C?
To solve this problem, we can use the formula:
R2 = R1 * (1 + α * ΔT)
where R1 is the resistance at the initial temperature, α is the temperature coefficient of resistance, ΔT is the change in temperature, and R2 is the resistance at the final temperature.
Given:
R1 = 80 ohms (at 15°C)
α = 0.004/°C
ΔT = 40°C - 15°C = 25°C
Substituting these values in the formula, we get:
R2 = 80 * (1 + 0.004 * 25)
R2 = 80 * 1.1
R2 = 88 ohms
Therefore, the resistance of the winding at 40°C will be 88 ohms.
To solve this problem, we can use the formula:
R2 = R1 * (1 + α * ΔT)
where R1 is the resistance at the initial temperature, α is the temperature coefficient of resistance, ΔT is the change in temperature, and R2 is the resistance at the final temperature.
Given:
R1 = 80 ohms (at 15°C)
α = 0.004/°C
ΔT = 40°C - 15°C = 25°C
Substituting these values in the formula, we get:
R2 = 80 * (1 + 0.004 * 25)
R2 = 80 * 1.1
R2 = 88 ohms
Therefore, the resistance of the winding at 40°C will be 88 ohms.
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The winding of a motor has a resistance of 80 ohms at 15°C. Find its resistance at 50° C. the temperature co-efficient of resistance is 0.004/°Ca)60.57Ωb)75.47Ωc)90.56Ωd)80.0ΩCorrect answer is option 'C'. Can you explain this answer?
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